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The change in internal energy of the system is +30 J
Explanation:
We can solve this problem by using the first law of thermodynamics, which states that the change in internal energy of a system is given by the equation:
where
is the change in internal energy
Q is the heat absorbed by the system (positive if it is absorbed, negative if it is released)
W is the work done by the system (positive if it is done by the system, negative if it is done by the surroundings on the system)
Therefore, in this problem, we have
(heat released by the system)
(work done on the system)
Therefore, the change in internal energy is
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Answer:
v=12.5 i + 12.5 j m/s
Explanation:
Given that
m₁=m₂ = m
m₃ = 2 m
Given that speed of the two pieces
u₁=- 25 j m/s
u₂ =- 25 i m/s
Lets take the speed of the third mass = v m/s
From linear momentum conservation
Pi= Pf
0 = m₁u₁+m₂u₂ + m₃ v
0 = -25 j m - 25 i m + 2 m v
2 v=25 j + 25 i m/s
v=12.5 i + 12.5 j m/s
Therefore the speed of the third mass will be v=12.5 i + 12.5 j m/s
