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Art [367]
4 years ago
5

In an experiment performed in a space station, a force of 60 N causes an object to have an acceleration equal to 4m/s. What is t

he object's mass?
Physics
1 answer:
Naddik [55]4 years ago
3 0

I'm afraid you're not paying attention.  This question is loaded with
all the important words, and you don't recognize Newton's second
law of motion.  Didn't you notice the  "force", "acceleration", and
"mass" all over the place in there ?

Newton's 2nd law:      Force = (mass) x (acceleration)

The answer is going to be 'mass', so let's divide
each side of Newton's law by 'acceleration':

                                   Mass = (force) / (acceleration)

Now, just write in the numbers that the question gave you:

                  force =  60 newtons
       acceleration =  4 m/s²

Here's the equation again:     Mass = (force) / (acceleration)      

                                                       = (60 N) / (4 m/s²)

                                                       =  15 kg .  

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A skateboarder is accelerating forward. How would his acceleration change if he had more mass?
exis [7]

Answer:

If the force remains the same, the acceleration would decrease

Explanation:

According to Newton's second law, the acceleration of an object is given by

a=\frac{F}{m}

where

F is the force applied to the object

m is the mass of the object

As we see from the formula, the acceleration a is inversely proportional to the mass, m. Therefore, if the force F remains constant, this means that if the mass of the skateboarder increases, then the acceleration will decrease.

4 0
4 years ago
A gas undergoes two processes. In the first, the volume remains constant at 0.170 m3 and the pressure increases from 1.50×105 Pa
Mnenie [13.5K]

Answer:

W_{T} = - 24 kJ

Explanation:

The work (W) done by the gas can be calculated using the following equation:

W = p*\Delta V = p*(V_{f} - V_{i})

<u>Where:</u>

p: is the pressure

[tex}V_{f}[/tex]: is the final volume

[tex}V_{i}[/tex]: is the initial volume

In the first process, the work done by the gas is:

W_{1} = p*\Delta V = p*0 = 0

Since the volume remains constant, the total work done by the gas is equal to zero.

In the second process, the work done by the gas is:

W_{2} = p*(V_{f} - V_{i}) = 6.00 \cdot 10^{5} Pa*(0.130 m^{3} - 0.170 m^{3}) = -24 kJ

Now, the total work done by the gas during both processes is:

W_{T} = W_{1} + W_{2} = 0 + (-24 kJ) = - 24 kJ

Therefore, the total work done by the gas during both processes is - 24 kJ.

I hope it helps you!

7 0
4 years ago
A pump is used to lift 100 KG of water from a wel 60 m deep,in 20 S If force of gravity on 1 KG is 10 N,find
Harlamova29_29 [7]

Explanation:

Given,

  • m = 100 kg
  • g = 10 N/kg¹
  • h = 60 m
  • t = 20 s

To Find:

a) Work done by the pump

b) Potential energy stored in the water

c)Power spent by the pump

d)Power rating of the pump.

Solution:

  • a) Work done by the pump

We know that,

\rm \: Work  \: done = Force * Distance  \: moved

  • f = 100 kg * 10N/kg
  • d = 60 m

\rm \: Work\; Done =(100 \: kg \times  \cfrac{10N}{kg} ) \times 60 \: m

\rm \: Work\; Done =1000 \times 60 \: joule

\boxed{\rm \: Work\; Done =60000 \: joule}

[The unit'll be joule since N×M = J]

  • b) Potential energy stored in the water

\rm \: P.E = m \cdot g \cdot  h

  • m = 100 kg
  • g = 10N/kg
  • h = 60

\rm \: P.E =100 \:kg \:  \times  \cfrac{10 \: N}{kg}  \times 60

\boxed{\rm \: P.E =60000  \: joule}

  • same condition here as well, N×M = J
  • c) Power of the Pump

\rm \: P = W/T

  • where P = Power; W = Work done & T = Time taken
  • As we got the value of work done on question (a),& ATQ time taken is 20 S.

\rm \: P =  \cfrac{60000 \: joule}{20 \: seconds}  =\boxed{\rm { 3000 \: Watts }}\: or \: \boxed{\rm 3 \: kW}

  • d) Power rating of the pump = 3 kW

Assumption: The pump is 100% efficient & works well.

6 0
2 years ago
A disk initially rotated counterclockwise at 1.0 rad/s, but has a counterclockwise angular acceleration of 0.50 rad/s^2 for 2 se
Mumz [18]

Answer:

Initial angular position of the disc is 3 radian

Explanation:

As we know that the angular acceleration of the disc is given as

\alpha = 0.50 rad/s^2

initial angular speed is given as

\omega = 1 rad/s

now we know that angular displacement of the disc is given as

\theta = \omega t + \frac{1}{2}\alpha t^2

\theta = 1(2) + \frac{1}{2}(0.5)(2^2)

\theta = 3 rad

now we have

\theta_f - \theta_i = 3 rad

6 rad - \theta_i = 3

\theta_i = 3 ard

8 0
3 years ago
A theory in science is ________.
Veseljchak [2.6K]

Answer:

It would be (a)

Explanation:

A theory is something that can be proved through rigorous and repeated experimentation, while choice (b) sounds tempting i believe it fails at the fact that it says that a theory is an "agreement", sure an agreement could be reached by while trained scientists but that does not necessarily mean that what the scientists agree upon is rigorously tested and repeatable, and so therefore cannot be assumed

That is what I think

Hope this helps :)  

3 0
3 years ago
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