Answer:
(a) Distance traveled = 75.3846 m
(b) Velocity of car at that instant will be 14 m/sec
Explanation:
We have given acceleration of the car 
Initial velocity of the cart u = 0 m/sec
(a) According to second equation of motion we know that 
So distance traveled by car 
As the truck is moving with constant speed
So distance traveled by truck 
As the truck overtakes the car
So 


So distance traveled 
(b) From second equation of motion we know that v = u+at
So v = 0+1.3×10.769 = 14 m /sec
Answer:
Right shoe
Explanation:
Let the mass and velocity of incoming puck be m and v respectively.
Momentum of the colliding puck will be mv
In case of first case , the momentum of puck becomes zero so change in momentum after collision with left shoe
= mv - 0 = mv
If time duration of collision be t
rate of change of momentum
= mv / t
This is the force exerted by puck on the left shoe .
Now let us consider collision with right shoe
momentum after collision with right shoe
- mv
change in momentum
= mv - ( - mv ) = 2mv
If time duration of collision be t
rate of change of momentum
= 2mv / t
This is the force exerted by puck on the right shoe .
Since the force on the right shoe is more , this shoe will have greater speed
after collision.
Answer:
1.02 seconds
Explanation:
Initial velocity = u = 5 m/s
t = Time taken
s = Displacement travelled = 0
a = Acceleration due to gravity = -9.81 m/s² (negative sign due to direction)
Equation of motion

So, time taken to return to its initial position is 1.02 seconds
A: Some physical properties change, but the substance keeps its identity.