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Sloan [31]
3 years ago
15

Missing value 0.003 x what = 3

Mathematics
1 answer:
Tomtit [17]3 years ago
3 0
2x=3
so substitute y=mx+c
rise/run
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Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C
netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

<span> |PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}</span></span>


Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.


|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5

|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6

|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4

|PD|= \sqrt{ (-2+6)^{2} + (-2+6)^{2}}= \sqrt{16+16}= \sqrt{32}\ \textgreater \  \sqrt{25}=5

|PE|= \sqrt{ (-2+5)^{2} + (-2-1)^{2}}= \sqrt{9+9}= \sqrt{16}=4


Answer: B and D





3 0
3 years ago
What is the solution of x=2+√x-2 ?
Blizzard [7]
C. \: x = 2 \: or \: x = 3
3 0
3 years ago
The shoes were $175. They are now 10% off. How much are they now?
kondor19780726 [428]

Sale Price = $157.5 (answer). This means the cost of the item to you is $157.5. You will pay $157.5 for a item with original price of $175 when discounted 10%. In this example, if you buy an item at $175 with 10% discount, you will pay 175 - 17.5 = 157.50 dollars.

Hope this helps!

3 0
3 years ago
How many solutions does this system have?
densk [106]

Answer:

One solution since x=0

6 0
3 years ago
If triangle ABC defined by the coordinates A(1,1), B(9,1), C(1,9) is dilated by a scale factor of 1/2
alukav5142 [94]

Answer:

The transformed points of the triangle ABC are A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right), B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right), C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)

Step-by-step explanation:

The new points after applying the scale factor are, respectively:

A' (x,y) = \frac{1}{2}\cdot (1,1)

A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)

B' (x,y) = \frac{1}{2}\cdot (9,1)

B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)

C'(x,y) = \frac{1}{2}\cdot (1,9)

C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)

7 0
3 years ago
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