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3 years ago

Can somebody please help me? Will mark brainliest ! 13 points

Mathematics

1 answer:

Mrrafil [7]3 years ago

8 0

Answer:

Look up the worksheet title on google and then answers. I have done this before and it has helped me. I hope this helps you!!!

Step-by-step explanation:

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You wonder if one's age is independent of whether or not one's willingness to wear masks in public. You ask 100 people whether t

antiseptic1488 [7]

Answer:

The statistical conclusion is:

a) Your results are significant; one's willingness to wear masks is not independent of one's age.

Step-by-step explanation:

From this experiment,

The null hypothesis is established as:

H 0 = one's willingness to wear masks is independent of one's age.

The alternate hypothesis is established as:

H 1 = one's willingness to wear masks is not independent of one's age.

In statistics, if the absolute value of the test statistic is greater than the critical value, we declare statistical significance and reject the null hypothesis.

Since the test statistic = 16.5, which is higher than the critical value of 7.82, this establishes statistical significance. Thus, the null hypothesis is rejected.

Therefore, the statistical conclusion is that one's willingness to wear masks is not independent of one's age.

7 0

3 years ago

A family has two cars. The first car has a fuel efficiency of 30 miles per gallon of gas and the second has a fuel efficiency of

Ugo [173]

One car 40 miles /gallon
other car 30 miles/gallon
..
Total miles = 165
gas used = 45 gallons
...
let first car drive x miles
second car drive y miles
..
x/40 + y/30 = 45
(30x+40y)/30*40 = 45
30x+40y = 45*40*30
30x+40y=54,000

6 0

3 years ago

Read 2 more answers

In Triangle ABC, the length of Segment AB is equal to the length of segment AC. The length of segment BC is 4 less than twice th

seraphim [82]

Step-by-step explanation:

Let x be the length of segment AB.

Then the length of segment BC is (2x - 4).

The length of segment AC is x.

We know that x + (2x - 4) + x = 52.

Therefore 4x - 4 = 52, 4x = 56, x = 14.

Hence the length of segment AB is 14.

7 0

3 years ago

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

3 years ago

amanda read 15 pages of her 150-page book in 2 hours. At this rate, how long will it take her to read the entire book?

irina [24]

20 hours. You find this by dividing 150 by 10 and then multiplying that by 2.

7 0

3 years ago

Read 2 more answers