Let x represent the amount michelle has.
The equation would be: 5x+7x+x=208
And to solve it you need to combine like terms: 5x+7x+x=13x
13x=208 divide both sides by 13 and you get that x equals to 16.
And this is how much each person got:
Michelle-16
Ian-80
Joe-112.
Plz thank you me. bye :)
550 sq m
Step-by-step explanation:
Step 1 :
The length of the first cross road the park is 70 m
The width of the first cross road the park is 5 m
So its area is 70 * 5 = 350 sq m
Step 2 :
The length of the second cross road the park is 45 m
The width of the width cross road the park is 5 m
So its area is 45 * 5 = 225 sq m
Step 3 :
The 2 cross roads intersect in the middle at an area of 5 * 5 = 25 sq m
This area is included in the computation of the area of both the cross roads and hence we need to subtract this area from the sum of the area of both the cross roads to obtain the actual area of cross roads in the park
So we have
the area of the cross roads inside the park = 350 + 225 - 25 = 550 sq m
Answer:
pizza: $4, coke: $3, chips: $2
Step-by-step explanation:
Lets make the price of a pizza=p a coke= k and a bag of chips=c
then we have the following equations
p+k+c=9
p+2k=10
2p+2c=12
Because p is common in all the equations we shall make it the subject of each equation.
p=9-(k+c)...........i
p=10-2k..............ii
p=6-c...................iii
We then equate i and iii
9-(k+c)=6-c
9-k-c=6-c
putting like terms together we get:
9-6=-c+c+k
1 coke, k=$3
replacing this value in equation ii
we get p=10-2(3)
p=10-6= 4
1 pizza, p=$4
replacing this value in equation iii
4=6-c
c=6-4
=2
a bag of chips, c=$2
Thus, a pizza, a coke and a bag of chips= pizza: $4, coke: $3, chips: $2
Answer:
<h2>x = 2</h2>
Step-by-step explanation:
Look at the picture.
Step-by-step answer:
assuming the true-false test have equal probabilities (each 0.5), we can use the binomial probability to calculate the sum of probabilities of getting 10, 11 or 12 questions correctly out of 12.
p=probability of success = 0.5
N=number of questions
x = number of correct answers
then
P(x) = C(N,x)(p^x)((1-p)^(N-x))
where C(N,x) = N!/(x!(N-x)!) = number of combinations of taking x objects out of N.
P(10) = C(12,10)(0.5^10)((1-0.5)^2) = 33/2048 = 0.01611
P(11) = C(12,11)(0.5^11)((1-0.5)^1) = 3/1024 = 0.00293
P(12) = C(12,12)(0.5^12)((1-0.5)^0) = 1/4096 = 0.00024
for a total probability of 79/4096 = 0.01929
