Answer:
P(A) = 86/100
P(B) = 79/100
P(A') = 14/100
P(A U B) = 95/100
P(A' U B) = 84/100
Step-by-step explanation:
i. P(A) = number of disks with high shock resistance/total number of disks
= (70+16)/100
= 86/100
ii. P(B) = number of disks with high scratch resistance/total number of disks
= (70+9)/100
= 79/100
iii. P(A') = number of disks without high shock resistance/total number of disks
= (100-86)/100
= 14/100
iv. P(AUB) = number of disks with high shock resistance or high scratch resistance/total number of disks
= (70+9+16)/100
= 95/100
v. P(A'UB) = number of disks without high shock resistance or with high scratch resistance/total number of disks
= (5+9+70)/100
= 84/100
Answer:
C
Step-by-step explanation:
In order to prove congruency using SSS, we need to prove that all three pairs of sides are congruent.
We are already given that EF ≅ HI and that FG ≅ IJ.
Therefore, the last bit of information we need to prove congruency using SSS is that EG ≅ HJ.
Hence, our answer is C.
Answer:
336x + 624
Step-by-step explanation:
A. (5,7)
b. (5,5)
c. (5,3)
d. (-2,5)
e. (-4,5)
f. (-6,5)
90
The correct Answer is B
