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3 years ago

If coordinate 5,7 is also in g(x), what is the domain of g(x)?

Mathematics

1 answer:

tekilochka [14]3 years ago

4 0

The left column of the table is domain + add the element 5

Mark brainliest please

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3 years ago

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If f(x) = (1/9)(9^x) what is f(3)

TiliK225 [7]

Answer: The required value of f(3) is 81.

Step-by-step explanation: We are given the following function :

$f(x)=\left(\dfrac{1}{9}\right)9^x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We are to find the value of f(3).

Substituting x = 3 in equation (i), we get

$f(3)\\\\\\=\left(\dfrac{1}{9}\right)\times9^3\\\\=9^2\\\\=81.$

Thus, the required value of f(3) is 81.

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3 years ago

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Is 25x²-40xy+16y²a perfect square number? why?

Crank

Answer:

yes

Step-by-step explanation:

25x² - 40xy + 16y² can be factored as

(5x - 4y)² ← a perfect square

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1 year ago

An equation and the steps to solve it are shown below:

Sphinxa [80]

S1: 7x - 4x - 2 = 6 OK
S2: 3x - 2 = 6 OK
S3: 3x - 2 + 2 = 6 WRONG, correct is 3x - 2 + 2 = 6 + 2

Answer: c. Step 3, because a number has been added only to one side of the equation.

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3 years ago

Please help me with this question

san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

Therefore,

$\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)$

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3 years ago

If coordinate 5,7 is also in g(x), what is the domain of g(x)?​

If coordinate 5,7 is also in g(x), what is the domain of g(x)?