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Mazyrski [523]
3 years ago
15

A 1,600 kg train car rolling freely on level track at 16 m/s bumps into a 1.0 × 103 kg train car moving at 10.0 m/s in the same

direction, and the two latch onto each other and continue together. What is their final speed?
A.) 16 m/s
B.) 6.0 m/s
C.) 10 m/s
D.) 14 m/s
Physics
1 answer:
emmainna [20.7K]3 years ago
6 0
This item is solved through the concept of the conservation of momentum which states that the momentum before and after collision should be equal. 
                                   momentum = mass x velocity
            (1,600 kg)(16 m/s) + (1.0x10^3 kg)(10 m/s) = (1600 + 1000 kg)(x)
The value of x is 13.69 m/s. Thus, their final speed is approximately letter D. 14 m/s. 
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4.156 m/s

Explanation:

See attachment

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Explanation :

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Greg is giving a slide show presentation to a large audience. It is very important to make the presentation informative. By using a laser, we can focus on the important part of the presentation. So that we can highlight the important points.

3 0
3 years ago
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How long will it take a 400 W engine to lift a 100 N object up to a height of 80 m?
Norma-Jean [14]
<h3>Answer:</h3>

20 seconds

<h3>Explanation:</h3>

<u>We are given</u>;

  • Power of the engine as 400 watts
  • Force as 100 N
  • Distance the object is lifted up as 80 m

We are required to determine the time taken.

  • We need to know that power is the rate of work done

Therefore;

  • Power = Work done ÷ time

But, work done  = Force × distance

  • Therefore; In this case;

Work done = 100 N × 80 m

                  = 8000 Joules

  • Since , Power = Work done ÷ time

Then, time = Work done ÷ Power

Thus;

Time = 8000 J ÷ 400 W

       = 20 s

Therefore, the time taken by the engine to lift the object is 20 seconds

4 0
3 years ago
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A ball player catches a ball 3.2 s after throwing it vertically upward. what height did it reach?
cluponka [151]

At the top of the height, the velocity is zero and acceleration is negative of acceleration due to gravity ( i.e  -9.8 m/s^2).

The time of the ball in air is 3.2 s, so ascending time is 3.2/2=1.6 s.

Therefore from kinematic equation,

v = u + gt

Substituting the values we get,

0= u - 9.8 (1.6)\\\\u=15.7 m/s, Here v = 0 at top.

Now from equation,

h=ut+\frac{1}{2} gt^2,  here h is the height .

So,

h=(15.7 m/s) (1.6s)-\frac{1}{2} 9.8m/s^2(1.6)^2\\\\ h=25.12m-12.54m\\\\h=12.48 m.

Thus, the ball reached at its maximum height of 12.48 m.

8 0
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daser333 [38]

Answer:E none of the above

Explanation:

When a space shuttle orbiting around the earth then earth gravitational force keeps the shuttle in its orbit by providing centripetal force. Tangential velocity makes the shuttle to revolve around the earth. Earth gravitational pull is significant to make the shuttle move in orbit while the Passengers feel weightlessness because they are falling downward but never able to reach as they move fast enough such that earth curves away them.                        

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