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maksim [4K]
3 years ago
9

A baseball is traveling (+20 m/s) and is hit by a bat. It leaves the bat traveling (-30 m/s). What is the change in the velocity

? Remember that direction is what makes velocity different than speed.
A. 50 m/s

B. 30 m/s

C. 20 m/s

D. 10 m/s
Physics
2 answers:
Reika [66]3 years ago
5 0

Answer: A. 50m/s

Explanation

Step 1

The first step is to define velocity.  Velocity is a measure of how fast displacement is changing with time. When discussing the velocity of a object we have to take into account that direction is important.

Step 2

The second step is to calculate the change in velocity.  The object is initially travelling with a velocity of +20m/s and then hits the bat, changes directions and travels at -30m/s in a direction opposite to it's initial direction. The change in velocity is calculated as shown below,

\Delta v=v_1-v_2\\\Delta v = +20m/s-(-30m/s)=+20m/s +30m/s = 50m/s.

The correct answer is 50m/s



djyliett [7]3 years ago
3 0

The answer is A. 50 m/s

I took the test and completed the study guide in class and got it correct.

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Answer:

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Explanation:

Given;

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P_1 + \rho gz_1 + \frac{1}{2}\rho v_1^2 =  P_2 + \rho gz_2 + \frac{1}{2}\rho v_2^2\\\\P_1 + \rho gz_1 + \frac{1}{2}\rho (0)^2 =  P_2 + \rho g(0) + \frac{1}{2}\rho v_2^2\\\\P_1 + \rho gz_1 =  P_2 + \frac{1}{2}\rho v_2^2\\\\P_{gauge} + P_{atm} + \rho gz_1 = P_{atm} + \frac{1}{2}\rho v_2^2\\\\P_{gauge} +  \rho gz_1 =  \frac{1}{2}\rho v_2^2\\\\v_2^2 = \frac{2(P_{gauge} +  \rho gz_1)}{\rho} \\\\v_2 = \sqrt{ \frac{2(P_{gauge} +  \rho gz_1)}{\rho} }

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