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finlep [7]
3 years ago
10

A boy having 0.2kg toy tied with a sting, having force 2N, angle 60º displaces it 5 m. What is the work done?

Physics
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

solution:

here,

force = 2N

displace=5m

then,

w =f*d

=2*5

=10 joule

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A 7750 kg space probe, moving nose-first toward Jupiter at 179 m/s relative to the Sun, fires its rocket engine, ejecting 72.0 k
Reika [66]

Answer:

179.47m/s

Explanation:

Using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

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Substitute

7750(179)+72(230) = (7750+72)v

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v = 1,403,810/7822

v= 179.47m/s

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How far apart would you have to place the poles of a 1. 5 v battery to achieve the same electric field?
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To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m

The potential difference is related to the electric field by:

∆V=Ed

where,

∆V is the potential difference

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d is the distance

what is potential difference?

The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.

We want to know the distance the detectors have to be placed in order to achieve an electric field of

E=1v/cm=100v/cm

when connected to a battery with potential difference

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Solving the equation,we find

d =  \frac{ \:Δv}{e}

=  \frac{1.5v}{100v/m}

= 1.5 \times 10 {}^{ - 2} m

learn more about potential difference from here: brainly.com/question/28166044

#SPJ4

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