Answer:
The answer to your question is:
a) 2.7 m/s²
b) -3.6 m/s²
Explanation:
Data
mass of the toolbox = 3.2 kg
a = ?
F = 40 N and F = 20 N
g = 9.81 m/s²
Formula
Second law of motion = F = ma
a + g = F / m
a = F/m - g
a) a = 40/3.2 - 9.81
a = 2.69 ≈ 2.7 m/s² positive up
b) a = 20/ 3.2 - 9.81
a = 6.25 - 9.81
= - 3.56 ≈ - 3.6 m/s² negative down
Answer:
sorry but which class your talking 'bout
Answer:
the air within our bodies (in our lungs and stomachs, for example) is exerting the same pressure outwards so there's no pressure difference and no need for us to exert any effort.
Explanation:
Answer:
e=58%
Explanation:
Given data
The Otto-cycle engine in a Mercedes-Benz SLK230 has a compression ratio of 8.8.
Solution
We want to calculate the ideal efficiency of the engine when ratio of heat capacity for gas used γ=1.40. Ideal efficiency (e) of the Otto cycle given by:
Substitute the given values to find efficiency e
e=58%