A boy having 0.2kg toy tied with a sting, having force 2N, angle 60º displaces it 5 m. What is the work done?

A saturated solution is formed by keeping 48 gram of a salt in 200 gram of water at 35°C. calculate the solubility of the salt.

viva [34]

The solubility of the salt. : 24 g/100 g solvent(water)

<h3>Further explanation</h3>

Given

48 gram of a salt in 200 gram of water at 35°C

Required

The solubility of the salt.

Solution

Solubility : the amount of a substance that can be dissolved in a solvent

Can be formulated(for 100 g solution)⇒grams solute per 100 g of solvent(100 ml water)

$\tt solubility=\dfrac{mass~solute}{mass~solvent}\times 100$

Input the value :

$\tt solubilty=\dfrac{48~}{200~g}\times 100=24~g$

4 0

3 years ago

What is the change in length of a 1400. m steel, (12x10^-6)/(C0) , pipe for a temperature change of 250.0 degrees Celsius? Remem

8090 [49]

Answer:

$\Delta L = 4.2 m$

Explanation:

As per the formula of thermal expansion we know that

$L = L_o(1 + \alpha\Delta T)$

so here we will have

$L_o = 1400 m$

$\alpha = 12 \times 10^{-6} per ^oC$

$\Delta T = 250 degree C$

so here change in the length of the rod is given as

$\Delta L = L - L_o$

$\Delta L = L_o \alpha \Delta T$

$\Delta L = 1400 (12 \times 10^{-6})(250)$

$\Delta L = 4.2 m$

8 0

4 years ago

Part A: Determine the wavelength of photons that can be emitted

torisob [31]

Answer:

A λ = 97.23 nm

, B) λ = 486.2 nm

, C) λ = 53326 nm

Explanation:

With that problem let's use the Bohr model equation for the hydrogen atom

$E_{n}$ = -k e² /2a₀ 1/n²

For a transition between two states we have

$E_{nf}$ - $E_{no}$ = -k e² /2a₀ (1/ $n_{f}$ ² - 1 / n₀²)

Now this energy is given by the Planck equation

E = h f

And the speed of light is

c = λ f

Let's replace

h c / λ = - k e² /2a₀ (1 / $n_{f}$ ² - 1 / no₀²)

1 / λ = - k e² /2a₀ hc (1 / $n_{f}$ ² -1 / n₀²)

Where the constants are the Rydberg constant $R_{H}$ = 1.097 10⁷ m⁻¹

1 / λ = $R_{H}$ (1 / n₀² - 1 / nf²)

Now we can substitute the given values

Part A

Initial state n₀ = 1 to the final state $n_{f}$ = 4

1 / λ = 1.097 10⁷ (1/1 - 1/4²)

1 / λ = 1.0284 10⁷ m⁻¹

λ = 9.723 10⁻⁸ m

We reduce to nm

λ = 9.723 10⁻⁸ m (10⁹ nm / 1m)

λ = 97.23 nm

Part B

Initial state n₀ = 2 final state $n_{f}$ = 4

1 / λ = 1.097 10⁷ (1/2² - 1/4²)

1 / λ = 0.2056 10⁻⁷ m

λ = 486.2 nm

Part C

Initial state n₀ = 3

1 / λ = 1,097 10⁷ (1/3² - 1/4²)

1 / λ = 5.3326 10⁵ m⁻¹

λ = 5.3326 10-5 m

λ = 53326 nm

5 0

3 years ago

At a particular instant the magnitude of the gravitational force exerted by a planet on one of its moons is 7 × 1021 N. Collapse

9966 [12]

Answer:

Fg = 4.2*10²² N

Explanation:

The gravitational force between any two masses, provided that can be approximated by point masses (comparing their diameters with the distance between them), obeys the Newton's Universal Law of Gravitation, which states that the force (always attractive) is proportional to the product of the masses and inversely proportional to the square of the distance between them (this as a consequence of our Universe being three-dimensional), as follows:

$Fg =\frac{G*m1*m2}{r^{2}}$

So, if one of the masses increases 6 times, the force between them will be directly 6 times larger, so the new magnitude of the force will be as follows:

Fg₂ = Fg₁*6 = 7*10²¹ N* 6 = 4.2*10²² N

7 0

3 years ago

Which of these galaxies would you most likely find at the center of a large cluster of galaxies?

Paul [167]

Answer:

a large elliptical galaxy

Explanation:

4 0

2 years ago