Answer:
a) The magnitude of the magnetic field = 7.1 mT
b) The direction of the magnetic field is the +z direction.
Explanation:
The force, F on a current carrying wire of current I, and length, L, that passes through a magnetic field B at an angle θ to the flow of current is given by
F = (B)(I)(L) sin θ
F/L = (B)(I) sin θ
For this question,
(F/L) = 0.113 N/m
B = ?
I = 16.0 A
θ = 90°
0.113 = B × 16 × sin 90°
B = 0.113/16 = 0.0071 T = 7.1 mT
b) The direction of the magnetic field will be found using the right hand rule.
The right hand rule uses the first three fingers on the right hand (the thumb, the pointing finger and the middle finger) and it predicts correctly that for current carrying wires, the thumb is in the direction the wire is pushed (direction of the force; -y direction), the pointing finger is in the direction the current is flowing (+x direction), and the middle finger is in the direction of the magnetic field (hence, +z direction).
Answer:the rate changes during the position of the object
Explanation:so there is no object that has the same rate but unless it is a specific one like a care but it changes during the position of the object
Answer:
v = 344.1 m / s
d = 1720.5 m
Explanation:
For this problem we must calculate the speed of sound in air at 22ºC
v = 331 RA (1+ T / 273)
we calculate
v = 331 RA (1 + 22/273)
v = 344.1 m / s
the speed of the wave is constant,
v = d / t
d = v t
we calculate
d = 344.1 5
d = 1720.5 m
Answer:
The Density of the block is 4.667g/mL
Explanation:
Given the following data;
Mass of block = 700g
Volume of block = 150cm³
Density = ?
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
![Density = \frac{mass}{volume}](https://tex.z-dn.net/?f=Density%20%3D%20%5Cfrac%7Bmass%7D%7Bvolume%7D)
Substituting into the equation, we have;
![Density = \frac{700}{150}](https://tex.z-dn.net/?f=Density%20%3D%20%5Cfrac%7B700%7D%7B150%7D)
<em>Density = 4.667g/mL</em>
Given :
Initial velocity , u = 0 m/s .
Acceleration due to gravity on moon ,
.
Height , h = 2 m .
To Find :
Final position after falling for 1.5 seconds .
Solution :
We know , by equation of motion :
![s=ut+\dfrac{at^2}{2}](https://tex.z-dn.net/?f=s%3Dut%2B%5Cdfrac%7Bat%5E2%7D%7B2%7D)
Here ,
.
So , equation will transform by :
![s=ut+\dfrac{g_mt^2}{2}\\\\s=0+\dfrac{1.67\times 1.5^2}{2}\ m\\\\s=1.88\ m](https://tex.z-dn.net/?f=s%3Dut%2B%5Cdfrac%7Bg_mt%5E2%7D%7B2%7D%5C%5C%5C%5Cs%3D0%2B%5Cdfrac%7B1.67%5Ctimes%201.5%5E2%7D%7B2%7D%5C%20m%5C%5C%5C%5Cs%3D1.88%5C%20m)
Therefore , the height form moon's surface is 1.88 m .
Hence , this is the required solution .