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3 years ago

Please help asap 100 POINTS and BRAINLIEST to best answer.

Physics

2 answers:

andrew11 [14]3 years ago

6 0

D. :)

lmk if im right or wrong

borishaifa [10]3 years ago

6 0

Answer:

D. 5ºC

Explanation:

Not B, because 1k= -457.87 fahrenheit. That means it is also not C. Since the icicles are melting, then that means it is not A either.

5ºC=about 41ºF

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3 years ago

Olivia is on a swing at the playground at which point is her kinetic energy increasing and her potential energy decreasing

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Whenever an object is falling, its potential energy
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3 years ago

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vaieri [72.5K]

Answer:

(A) Pepsin

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From the graph it is clear that pepsin is the only enzyme which works in highly acidic condintion in the digestive system.

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3 years ago

Pls help with all questions dew in 10 minutes!

Artyom0805 [142]

7.Jupiter is the largest planet in our solar system at nearly 11 times the size of Earth and 317 times its mass.

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The second largest planet in the solar system

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3 years ago

A 125-kg astronaut (including space suit) acquires a speed of 2.50 m/s by pushing off with her legs from a 1900-kg space capsule

ryzh [129]

(a) 0.165 m/s

The total initial momentum of the astronaut+capsule system is zero (assuming they are both at rest, if we use the reference frame of the capsule):

$p_i = 0$

The final total momentum is instead:

$p_f = m_a v_a + m_c v_c$

where

$m_a = 125 kg$ is the mass of the astronaut

$v_a = 2.50 m/s$ is the velocity of the astronaut

$m_c = 1900 kg$ is the mass of the capsule

$v_c$ is the velocity of the capsule

Since the total momentum must be conserved, we have

$p_i = p_f = 0$

$m_a v_a + m_c v_c=0$

Solving the equation for $v_c$ , we find

$v_c = - \frac{m_a v_a}{m_c}=-\frac{(125 kg)(2.50 m/s)}{1900 kg}=-0.165 m/s$

(negative direction means opposite to the astronaut)

So, the change in speed of the capsule is 0.165 m/s.

(b) 520.8 N

We can calculate the average force exerted by the capsule on the man by using the impulse theorem, which states that the product between the average force and the time of the collision is equal to the change in momentum of the astronaut:

$F \Delta t = \Delta p$