Considering the unknown resistence as R and using the Ohm's First Law, we have:

$i= \frac{V}{R_{eq}} \\ 0.5= \frac{12}{R+10} \\ R+10=24 \\ R=14-Ohm$

The equivalent resistence is given by the resistor series with the lamp resistence.

$R_{eq}=R+10 \\ R_{eq}=14+10 \\ \boxed {R_{eq}=24-Ohm}$

If you notice any mistake in my english, please let me know, because i am not native.

6 0

3 years ago

PLSS HELP!!! THIS IS URGENT

Fed [463]

Answer:

D. Sand carried by rivers flows over and weathers the rocks.

Explanation:

The sand in the river is move because of the flow of the river and as the sand moves it grinds on the rocks in the river. This starts a process know as abrasion, in other words it means that it wheathers(grinds) against the rocks.

3 0

2 years ago

Two charged particles are placed 2.0 meters apart. The first charge is +2.0 E-6 C, and the second charge is +4.0 E-6 C. What is

ipn [44]

F = kq1q2/r^2

q1 is first charge 
q2 is second charge 
k is 9 E9 
r is distance between them 

F = (9E9)(2 E-6)(4 E-6)/2^2 = 0.018 N 

A postive answer indicates a repulsive force

4 0

3 years ago