Answer:
K
Explanation:
Given that
Elements Density
K 0.86 g/cm³
Ca 1.5 g/cm³
Sc 3.2 g/cm³
Ti 4.5 g/cm³
As we know that density of the BCC ( body centered cubic )element is lower than the FCC(Face centered cubic )element.
In the given problem only K have lower density all of these element that is why is in BCC and all others are in FCC.
The packing efficiency of the FCC structure element is higher than the BCC element that is why FCC is more denser than BCC.And also FCC having good packing of element.
Answer: short displacement has shorter road and long displacement has longer displacement . now think your self Which one is right
Answer:
6,600N
Explanation:
According to second law of motion, Force = mass × acceleration
If acceleration = change in velocity/time = 15/0.10
Acceleration = 150m/s²
Given mass = 44kg
Force = 44× 150
Force = 6,600N
Magnitude of the average force exerted on the passenger during this time is 6,600N
Answer:
Refer to the attachment for solution (1).
<h3><u>Calculating time taken by it to stop (t) :</u></h3>
By using the second equation of motion,
→ v = u + at
- v denotes final velocity
- u denotes initial velocity
- t denotes time
- a denotes acceleration
→ 0 = 5 + (-5/6)t
→ 0 = 5 - (5/6)t
→ 0 + (5/6)t = 5
→ (5/6)t = 5
→ t = 5 ÷ (5/6)
→ t = 5 × (6/5)
→ t = 6 seconds
→ Time taken to stop = 6 seconds
