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Jet001 [13]
3 years ago
14

The mechanism of chymotrypsin can be viewed as a two-step process, acylation of the enzyme active site followed by a deacylation

reaction. The observation of "burst" kinetics in rapid kinetic studies of the hydrolysis of p-nitrophenylphosphate by chymotrypsin is due to:_______
A. the rate of the acylation reaction being faster than the deacylation reaction.
B. the rates of acylation and deacylation being equal.
C. the rate of the acylation reaction being slower than the deacylation reaction.
Chemistry
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

A. the rate of the acylation reaction being faster than the deacylation reaction.

Explanation:

Chymotrypsin belongs to a class of enzymes known as proteases; enzymes that catalyse the cleavage of peptide bonds by hydrolysis.

The mechanism of chymotrypsin catalysis occurs in two distinct phases; (1) an acylation phase where the peptide bond is cleaved and an ester linkage is formed between the peptide carbonyl carbon and the enzyme, (2) a deacylation phase where the ester linkage is hydrolyzed and the non-avylated enzyme is regenerated.

In studies by B.S. Hartley and B.A. Kilby in 1954 of chymotrypsin hydrolysis of the ester p-nitropheylacetate, as measured by the release of nitrophenol, it was discovered that it proceeded with a burst before leveling of to a slower rate. This burst was due to a rapid acylation of all the enzyme molecules with a slow deacylation limiting the turnover of the enzyme.

Similarly, the observation of burst kinetics in rapid kinetic studies of the hydrolysis of p-nitrophenylphosphate by chymotrypsin is due to the initial phase of acylation proceeding much faster than the later phase of deacylation of the enzyme.

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What happens when the electron moves from the first energy level to the second energy level?
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There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with
grandymaker [24]

\text{Hg} \text{O} and \text{Hg}_{2} \text{O}.

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n = m/M; 0.6498 \; g of the first compound would contain

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Oxygen and mercury atoms seemingly exist in the first compound at a 1:1 ratio; thus the empirical formula for this compound would be \text{Hg} \text{O} where the subscript "1" is omitted.

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\text{Hg}_{2} \text{O}.

8 0
3 years ago
Perform the following calculations to the correct number of significant figures.
SSSSS [86.1K]
Answer: 460.624

Explanation:
1. Multiply the numbers
(24.5260 x 2.56) + 397.84
= (62.784) + 397.84

2. Add the numbers
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4 0
2 years ago
How many electron are in 56fe 3
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Each proton has a charge of +1. The other particle present in the nucleus - the neutron - has zero electrical charge and thus irrelevant when computing the charge of a nucleus. It is easy to deduce that the nucleus charge equals the number of protons (which in turn equals the atomic number). So the nucleus charges are:
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You typed 3. Is it accidental? If so, then the answer is above. If not, then you could be trying to type 56Fe +3, which means an ionic iron with charge +3. Charges are formed when you have too many or too few electrons to counter-balance the prositive charge of the nucleus. Charge +3 means you're 3 electrons short to negate the nucleus positive charge.

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