Why does the electrical conductivity of ionic compounds change when they are dissolved in water?
1 answer:
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Answer:
Keq = 1.17 × 10²⁰
Explanation:
Let's consider the following redox reaction.
Cu²⁺(aq) + Ni(s) → Cu(s) + Ni²⁺(aq)
We can identify 2 half-reactions.
Cathode (reduction): Cu²⁺(aq) + 2 e⁻ → Cu(s) E°red = 0.337 V
Anode (oxidation): Ni(s) → Ni²⁺(aq) + 2 e⁻ E°red = -0.257 V
The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E° = E°red, cat - E°red, an = 0.337 V - (-0.257V) = 0.594 V
We can calculate the equilibrium constant (Keq) using the following expression.
where,
n are the moles of electrons transferred
Answer: The percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.
Explanation:
Given: Volume of solute = 120 mL
Volume of solvent = 350 mL
Now, total volume of the solution is as follows.
Let us assume that 100 mL of solution is taken and the amount of isopropyl alcohol present in it is as follows.
Hence, there is 25.53 mL isopropyl alcohol is present in 100 mL of solution. Therefore, %v/v is calculated as follows.
Thus, we can conclude that the percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.