The question is incomplete, the complete question is:
When aqueous solutions of NaCl and
are mixed, a solid forms. Determine the mass of solid formed when 140.7 mL of 0.1000 M NaCl is mixed with an excess of an aqueous solution of
<u>Answer:</u> The mass of lead chloride produced is 1.96 g
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
.....(1)
Given values:
Molarity of NaCl = 0.1000 M
Volume of the solution = 140.7 mL
Putting values in equation 1, we get:
![0.1000=\frac{\text{Moles of NaCl}\times 1000}{140.7}\\\\\text{Moles of NaCl}=\frac{0.1000\times 140.7}{1000}=0.01407mol](https://tex.z-dn.net/?f=0.1000%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20NaCl%7D%5Ctimes%201000%7D%7B140.7%7D%5C%5C%5C%5C%5Ctext%7BMoles%20of%20NaCl%7D%3D%5Cfrac%7B0.1000%5Ctimes%20140.7%7D%7B1000%7D%3D0.01407mol)
The chemical equation for the reaction of NaCl and lead nitrate follows:
![Pb(NO_3)_2(aq)+2NaCl(aq)\rightarrow PbCl_2(s)+2NaNO_3(aq)](https://tex.z-dn.net/?f=Pb%28NO_3%29_2%28aq%29%2B2NaCl%28aq%29%5Crightarrow%20PbCl_2%28s%29%2B2NaNO_3%28aq%29)
By the stoichiometry of the reaction:
If 2 moles of NaCl produces 1 mole of lead chloride
So, 0.01407 moles of NaCl will produce =
of lead chloride
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
......(2)
Molar mass of lead chloride = 278.1 g/mol
Plugging values in equation 2:
![\text{Mass of lead chloride}=(0.007035mol\times 278.1g/mol)=1.96g](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20lead%20chloride%7D%3D%280.007035mol%5Ctimes%20278.1g%2Fmol%29%3D1.96g)
Hence, the mass of lead chloride produced is 1.96 g