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nika2105 [10]
3 years ago
5

Soup ordinarily priced at 2 cans for .33 cents may be purchased in lots of one dozen for 1.74, what is the savings per a can whe

n it is purchased in this way
Mathematics
1 answer:
Sidana [21]3 years ago
5 0

Answer:

Savings per can would be 0.02 cents when purchased in lots.

Step-by-step explanation:

Given:

Ordinary price of soup 2 cans = 0.33 cents.

When purchases in lots 12 cans = 1.74

We need to find the saving per can when purchased in Lots.

Solution:

Ordinary price of soup 2 cans = 0.33 cents.

1 can  = Cost of 1 can when purchased ordinary.

By Using Unitary method we get;

Cost of 1 can when purchased ordinary = \frac{0.33}{2} = 0.165\ cents/can

Now we will find the Cost of 1 can when purchased in lot.

12 cans = 1.74

1 can = Cost of 1 can when purchase in lot.

Again by using Unitary method we get;

Cost of 1 can when purchase in lot = \frac{1.74}{12} = 0.145\ cents/can

Savings = Cost of 1 can when purchase in lot - Cost of 1 can when purchased ordinary

Savings = 0.165-0.145=0.02\ cents/can

Hence Savings per can would be 0.02 cents when purchased in lots.

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the surface area of a cuboid is 95cm² and its lateral surface area is 63cm². find the area of its base​
wel

Answer:

The Area of the base is 16 cm² .

Step-by-step explanation:

Given as :

The surface area of the cuboid = x = 95 cm²

The lateral surface area of the cuboid = y = 63 cm²

Let The Area of the base = z cm²

Now, Let The length of cuboid = l cm

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The height of cuboid = h cm

<u>According to question</u>

∵ The surface area of the cuboid = 2 ×(length × breadth + breadth × height + height × length)

Or, x = 2 ×(l × b + b × h + h × l)

Or, 95 =  2 ×(l × b + b × h + h × l)

Or,  (l × b + b × h + h × l) = \dfrac{95}{2}          ....1

<u>Similarly</u>

∵lateral surface area of the cuboid = 2 ×(breadth × height + length × height)

Or, y = 2 ×(b × h + l × h)

Or, 2 ×(b × h + l × h) = 63

Or, (b × h + l × h) = \dfrac{63}{2}              ......2

Putting value of eq 2 into eq 1

so,  (l × b +  \dfrac{63}{2} ) = \dfrac{95}{2}    

Or, l × b = \dfrac{95}{2} - \dfrac{63}{2}    

Or,  l × b = \dfrac{95 - 63}{2}

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so, l × b = 16

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Solve the system using substitution.<br> y - 3x = 1<br> 2y - x = 12<br> ([?], [])
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Answer:

(2, 5)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

y - 3x = 1

2y - x = 12

<u>Step 2: Rewrite Systems</u>

y - 3x = 1

  1. Add 3x on both sides:                    y = 3x + 1

<u>Step 3: Redefine Systems</u>

y = 3x + 1

2y - x = 12

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                    2(3x + 1) - x = 12
  2. Distribute 2:                         6x + 2 - x = 12
  3. Combine like terms:           5x + 2 = 12
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  5. Isolate <em>x</em>:                              x = 2

<u>Step 5: Solve for </u><em><u>y</u></em>

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  2. Substitute in <em>x</em>:                       2y - 2 = 12
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