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djverab [1.8K]
3 years ago
6

A right triangle has an area of 2k^2-k-15 One of the legs has a length of k^2-9 What is the ratio of the area of a triangle to t

he leg?
Mathematics
1 answer:
Darya [45]3 years ago
4 0
<h3>Given</h3>

A = 2k² -k -15

L = k² -9

<h3>Find</h3>

A/L

<h3>Solution</h3>

\displaystyle\frac{A}{L}=\frac{2k^2-k-15}{k^2-9}=\frac{(k-3)(2k+5)}{(k-3)(k+3)}\\\\=\frac{2k+5}{k+3}

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