Question

A right triangle has an area of 2k^2-k-15 One of the legs has a length of k^2-9 What is the ratio of the area of a triangle to the leg?

Answer 1

Given

A = 2k² -k -15

L = k² -9

Find

A/L

Solution

$\displaystyle\frac{A}{L}=\frac{2k^2-k-15}{k^2-9}=\frac{(k-3)(2k+5)}{(k-3)(k+3)}\\\\=\frac{2k+5}{k+3}$