2100/1 or 4200/2, could be either
$0.03+$0.04=$0.15x4=$0.60
If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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Answer:
She has walked <u>7233.6 ft</u>
Step-by-step explanation:
13.7 miles ÷ 10 = 1.37 miles
1 mile = 5280 ft
5280 x 1.37 = 7233.6 ft (or 7234 if rounded to the nearest ft)
Circumference=24 pi
Area=144 pi, shown clearly in photo
