Answer:
θ = 66º
Explanation:
This exercise of Newton's second law must be solved in part, let's start by finding the slowing down acceleration of the ball
a = v² / r
the radius of the circle is
sin θ = r / L
r = L sin θ
we substitute
a = v² /L sin θ
now let's write Newton's second law
vertical axis
T_y -W = 0
T_y = W
radial axis
Tₓ = m a (1)
let's use trigonometry for the components of the string tension
cos θ = T_y / T
sin θ = Tₓ / T
Tₓ = T sin θ
we substitute in 1
T sin θ =
T L sin² θ = m v²
we write our system of equations
T cos θ = m g
T L sin ² tea = m v²
we divide the two equations
L = v² / g
(1 -cos²)/ cos θ =
1 - cos² θ = cos θ
cos² θ + 0.97044 cos θ -1 = 0
we change variable cos θ = x
x² + 0.97044 x - 1 =0
x=
since the square root is imaginary there is no real solution to the problem, suppose that the radius is 1 m r = 1 m
T sin θ =
T cos θ = m g
resolved
tan θ =
θ = tan⁻¹ ( 4.75²/ 1 9.81)
θ = 66º
Answer:
I'm not taking physics right now but I would love too.
Explanation:
<h3>Answer;</h3>
<u>It would make the lens stronger. </u>
<h3>Explanation;</h3>
- The focal length is the distance between the optical center or the center of the lens to the focal point of a convex or concave lens.
- The power of the convex lens is lens ability to undertake refraction or bend light. It is given as the reciprocal of focal length.
- Power of the lens = 1/ f; therefore the smaller the focal length the higher the power and the larger the focal length the lower the power.
- Thus; decreasing the focal length of a convex lens makes the lens stronger.
Answer:
A. N = L/πD
B. N = 389 turns
C. L₂ = DN
D. L₂ = 17.5 m
E. B = 2.3 x 10⁻⁴ Web
Explanation:
A.
For each number of turn a length of wire equal to the circumference of tube. Therefore, the no. of turns can be given as:
N = L/2πr
<u>N = L/πD</u>
where,
N = No. of turns
D = Diameter of tube
L = Length of wire
B.
using values in the equation, we get:
N = 55 m/π(0.045 m)
<u>N = 389 turns</u>
C.
Since, there is only one layer of loop. Therefore, the length of solenoid can be easily found out by adding the diameter of wire for each turn. Hence:
L₂ = DN
where,
L₂ = Length of the solenoid
D = diameter of wire
N = No. of Turns
D.
using values in the equation we get:
L₂ = (0.045 m)(389)
<u>L₂ = 17.5 m</u>
<u></u>
E.
The magnitude of magnetic field inside solenoid is given by the formula:
B = μ₀NI/L₂
where,
B = Magnetic field inside solenoid
μ₀ = permeability = 4π x 10⁻⁷ T/A.m
I = current = 8.5 A
Therefore,
B = (4π x 10⁻⁷ T/A.m)(389)(8.5 A)/17.5 m)
<u>B = 2.3 x 10⁻⁴ Web</u>