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Ratling [72]
3 years ago
15

What is the most commonly used method of food preservation today? refrigeration drying foods smoking raw meats salt curing

Physics
2 answers:
dmitriy555 [2]3 years ago
6 0
Refrigerator was what is commonly used today. We do dry foods and salt cure but that is not done on a daily basis
klasskru [66]3 years ago
3 0

Answer: Refrigeration

Explanation: Food preservation is the technique of preserving food items from spoiling. It is done by preventing the growth of microorganisms and preventing the rancidity of fats.

In ancient times, the methods used for preservation of foods were drying foods which remove water and thus reduces the bacterial growth, smoking raw meats also hampers the bacterial activity and salt curing leads to osmosis and thus the bacteria dies.

The latest method is refrigeration which makes the food colder and the rate of deterioration gets slow. Bacterial action reduces with refrigeration, as bacteria cannot survive at low temperatures.

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Food provide your body with
Levart [38]
The food you eat every day provides the nutrients you need to survive. These food components include the macronutrients – protein, carbohydrate and fat – that offer calories as well as play specific roles in maintaining your health. Micronutrients, such as vitamins and minerals, don’t act as an energy source but do serve a variety of critical functions to ensure your body operates as optimally as possible.
7 0
2 years ago
Why concave lens is called diverging lens​
dangina [55]

When a parallel beam of light passes through a convex lens, the rays become farther from one another when the come out. This process of rays is called ''to diverge''. The concave lens makes rays of light diverge, so it is called diverging lens.

6 0
2 years ago
While traveling along a highway a driver slows from 31 m/s to 15 m/s in 8 seconds. What is the automobile’s acceleration? (Remem
MaRussiya [10]

Answer:

The automobile's acceleration in that time interval is -2 m/s^2

Explanation:

The acceleration is defined as the rate of change of the velocity.

The average acceleration in a given lapse of time is calculated as:

A = (final velocity - initial velocity)/time.

In this case, we have:

initial velocity = 31 m/s

final velocity = 15 m/s

time = 8 seconds.

Then the average acceleration is:

A = (15m/s - 31m/s)/8s = -2 m/s^2

8 0
2 years ago
The electrons in the beam of a television tube have an energy of 19.0 keV. The tube is oriented so that the electrons move horiz
igomit [66]

Answer:

The direction is due south

Explanation:

From the question we are told that

     The energy of the electron is E = 19.0keV = 19.0 *10^3 eV

      The earths magnetic field is B = 42.3 \muT = 42.3 *10^{-6} T

     

Generally the force on the electron is perpendicular to the velocity of the elecrton and the magnetic field and this is mathematically reresented as

          \= F = q (\= v * \=B)

On the first uploaded image is an  illustration of the movement of the electron

    Looking at the diagram  we can see that in terms of direction  the magnetic force  is

             \= F  =q(\=v * \= B)= -( -\r i * - \r k)

                = -(- (\r i * \r k))

generally  i cross k = -j

      so the equation above becomes

             \= F = -(-(- \r j))

                = - \r j

This show that the direction is towards the south  

 

3 0
3 years ago
What must be the length of a simple pendulum if its oscillation frequency is to be equal to that of an air-track glider of mass
Anvisha [2.4K]

Answer:

the length of the simple pendulum is 0.25 m.

Explanation:

Given;

mass of the air-track glider, m = 0.25 kg

spring constant, k = 9.75 N/m

let the length of the simple pendulum = L

let the frequency of the air-track glider which is equal to frequency of simple pendulum = F

The oscillation frequency of air-track glider is calculated as;

F = \frac{1}{2\pi } \sqrt{\frac{k}{m} } \\\\F = \frac{1}{2\pi } \sqrt{\frac{9.75}{0.25} } \\\\F = 0.994 \ Hz

The frequency of the simple pendulum is given as;

F = \frac{1}{2\pi} \sqrt{\frac{g}{l} } \\\\2\pi(F) = \sqrt{\frac{g}{l} } \\\\2\pi (0.994) = \sqrt{\frac{9.8}{l} } \\\\6.2455 = \sqrt{\frac{9.8}{l} } \\\\(6.2455)2 = \frac{9.8}{l} \\\\39.006 = \frac{9.8}{l} \\\\l = \frac{9.8}{39.006} \\\\l = 0.25 \ m

Thus, the length of the simple pendulum is 0.25 m.

8 0
2 years ago
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