Answer:
V = 192 kV
Explanation:
Given that,
Charge, 
Distance, r = 0.3 m
We need to find the electric potential at a distance of 0.3 m from a point charge. The formula for electric potential is given by :

So, the required electric potential is 192 kV.
Answer:
0.0619 m^3
Explanation
number of moles = n = 4.39 mol
pressure = P = 2.25 atm =2.25×1.01×10^5 Pa= 2.27×10^5 Pa
Molar gas constant =R = 8.31 J/(mol K)
Temperature T= 385K
volume of gas = V =?
BY GENERAL GAS LAW WE HAVE
PV = nRT
or V = nRT/P
or V = (4.39×8.31×385)/(2.27×10^5)
V = 0.0618728
V = 0.0619 m^3