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mojhsa [17]
3 years ago
7

A 4.88 x 10-6 C charge moves 265 m/s

Physics
2 answers:
rewona [7]3 years ago
7 0

Answer:

0 newtons

Explanation:

When a moving charge is parallel to the magnetic field, it feels no Magnetic force at all.

Even if the Magnetic Field is 100,000,000 Tesla!

Alex73 [517]3 years ago
5 0

Answer:

F=0N

Explanation:

From the question we are told that:

Charge Q=4.88 x 10-6 C

Velocity v= 265m/s

Angle \theta =0 \textdegree

Magnetic field B=0.0579T

Generally the equation for Force is mathematically given by

 F=Q(\=v*\=B)

 F=qvBsin\theta

Therefore

 F=qvBsin0 \textdegree

 F=0N

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A tray of electronic components contains 15 components, 4 of which are defective. If 4 components are selected, what is the poss
dlinn [17]

Answer:

a) 0.0007326

b) 0.03223

c) 0.2418

d) 0.2418

Explanation:

To find different probabilities for the selection of components among eleven good and four defective components, we will use the Combination.

a) C(4,4) = 1; C(15,4) = 1365

P = \frac{C(4,4)}{C(15,4)} = \frac{1}{1365} = 0.0007326

b) C(4,3) = 4; C(11,1) = 11

P = \frac{C(4,3)*C(11,1)}{C(15,4)} = \frac{4*11}{1365} = 0.03223

c) C(4,2) = 6; C(11,2) = 55

P = \frac{C(4,2)*C(11,2)}{C(15,4)} = \frac{6*55}{1365} = 0.2418

d) C(11,4) = 330

P = \frac{C(11,4)}{C(15,4)} = \frac{330}{1365} = 0.2418

8 0
3 years ago
Ten identical steel wires have equal lengths L and equal "spring constants" k. The Young's modulus of each wire is Y. The wires
svlad2 [7]

Answer:

option (B)

Explanation:

Young's modulus is defined as the ratio of longitudinal stress to the longitudinal strain.

Its unit is N/m².

The formula for the Young's modulus is given by

Y=\frac{F \times L}{A\times \delta L}

where, F is the force applied on a rod, L is the initial length of the rod, ΔL is the change in length of the rod as the force is applied, A is the area of crossection of the rod.

It is the property of material of solid. So, when the 10 wires are co joined together to form a new wire of length 10 L, the material remains same so the young' modulus remains same.

8 0
3 years ago
A silver wire with resistivity 1.59 × 10-8 Ω-m carries a current density of 4.0 A/mm2, What is the magnitude of the electric fie
Nat2105 [25]

Answer:

Electric field, E = 0.064 V/m

Explanation:

It is given that,

Resistivity of silver wire, \rho=1.59\times 10^{-8}\ \Omega-m

Current density of the wire, J=4\ A/mm^2=4\times 10^6\ A/m^2

We need to find the magnitude of the electric field inside the wire. The relationship between electric field and the current density is given by :

E=J\times \rho

E=4\times 10^6\times 1.59\times 10^{-8}

E = 0.0636 V/m

or

E = 0.064 V/m

So, the magnitude of electric field inside the wire is 0.064 V/m. Hence, this is the required solution.

6 0
3 years ago
An object has a mass of 25 kg. What is the force of gravity acting on the object?
aleksandrvk [35]

Answer:

25

Explanation:

Because u don't know the gravity so u take that force and just put it in the gravity spot

5 0
3 years ago
As a ship comes into view over the horizon the top appears before the rest of the ship how does this demonstrate the earth is sp
valina [46]
Since its a sphere, the top is seen first because its the tallest part if the ship. If the earth was flat, the whole ship would be seen.
7 0
3 years ago
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