The direction in which the magnetic force is acting on the charge is upwards.
<h3>What is Magnetic force?</h3>
This is the attraction and repulsion which usually occurs during the motion of electrically charged particles.
In the magnetic field, the charge is moving to the left. Therefore the direction the magnetic force is acting on the charge is upwards which is gotten via right hand rule.
Read more about Magnetic force here brainly.com/question/25932320
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The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.
<h3>Force exerted outside the wheel</h3>
The force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.
∑τ = 0
- Let the distance traveled by the load = 1.5 m
- Let the radius of the wheel or position of the force = 0.45 m
∑τ = R(mg) - r(F)
rF = R(mg)
0.45F = 1.5(21,200 x 9.8)
F = 6.925 x 10⁵ N.
Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.
Learn more about angular momentum here: brainly.com/question/7538238
Answer:
work done is 470400 J
Explanation:
given data
long = 3 m
wide = 2 m
deep = 4 m
density = 1000 kg/m³
to find out
Find the amount of work in joules
solution
we know here volume = area × length
so
area = 0.5 ×base×height
area = 0.5 ×2×4
area = 4 m²
so volume = 4 × 3 = 12 m³
and
weight of water = volume ×density×g
weight = 12 × 1000 × 9.8
weight = 117600 N
so
work done = weight × height
work done = 117600× 4
work done = 470400 J
0.05*0.2=0.05*0.15+0.015*m2',
m2'=1/6 m/s,
m2'=0.17 m/s
N I C E - D A Y!
