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sp2606 [1]
3 years ago
6

Write the function in vertex form. y=4x2 - 8x + 5

Mathematics
2 answers:
Tema [17]3 years ago
8 0

a=4, b=-8, c=5

h=-b/2a= -(-8)/2(4)

8/8=h=1

K= a(h)^2+b(h)+c

K= 4(1)^2-8(1)+5

K= 4-8+5

K= 1, Vertex  Form: a(x-h)^2+k

Vertex Form: Y= 4(X-(1)^2+K

Y= 4(x-1)^2+1

Firdavs [7]3 years ago
6 0
You will have to complete the square
factor the 4 out of the first two terms
y = 4(x^2 - 2x) + 5

x^2 - 2x + 1 = (x - 1)^2
we want what we have to look like this
the difference between (x^2 - 2x) and (x^2 - 2x + 1) is the +1
so we add a 1 and subtract a 1 to keep balance

y = 4(x^2 - 2x + 1  -1) + 5
y = 4(x^2 - 2x + 1) - 4 + 5   [moved the extra -1 out of it and distributive property]
y = 4(x - 1)^2 + 1   [factored and added like terms]

y = 4(x-1)^2 + 1
or
y - 1 = 4(x-1)^2

is now in vertex form.
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2 years ago
13
nlexa [21]

So say we have the number: 54,321

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7 0
3 years ago
-2{-7-2[3 squared + 2 to the power of 4]-8÷4}
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Answer:

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Step-by-step explanation:

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-2{-7-2{9+16]-2}

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118

5 0
3 years ago
Miss milliman reserving a room at the hotel India for a trip to see a show at the Fox Theater Hotel India charge of $717 for a t
sammy [17]
717/3= 239
 


Divide 717 by 3 to get the price of one night.
4 0
3 years ago
I really need help with this question answer nowwwwww please someone
natta225 [31]
Born: 7.45 pounds
gains: 6.4 oz a week
time: 1.5 months

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3 years ago
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