10•4=40. 40 is the perimeter of the square. To find the perimeter of the semicircle use the circle perimeter (circumference) formula and divide that answer by two. This would be pi•10. You get 31.4. Then divide by 2 so it’s 15.7. Finally add 15.7 and 40. Hope this helps... sorry it’s such a long answer
Answer:
Y= -3/5 - 1
Step-by-step explanation:
if you start on the y intercept an go down once (-1)
then go down three times (-3)
positive 5 so go right 5 times it lands on the point :)
im not a teacher and i took this last year so sorry if my explanation isn't the best
Answer:
Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and respectively.
Step-by-step explanation:
Given that,
For the first 9 holes X:
E(X) = 80
SD(X)=13
For the second 9 holes Y:
E(Y) = 80
SD(Y)=13
For the sum W=X+Y, the following properties holds for means , variance and standard deviation :
E(W)=E(X)+E(Y)
and
V(W)=V(X)+V(Y)
⇒SD²(W)=SD²(X)+SD²(Y) [ Variance = (standard deviation)²]
∴E(W)=E(X)+E(Y) = 80 +80=160
and
∴
Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and respectively.
Answer:
Height, base(4,1) to A(4,3)
Step-by-step explanation:
The height that is shown is incorrect as it is showing the distance between A and B, which is not the height of the triangle, and simply a side. We need to find the altitude(height) which is a line perpendicular to the base. If we draw a line that is perpendicular to the base that intersects the highest point of the triangle, A, we get the point of intersection of that line and the base at (4,1)
Answer: New function is
Step-by-step explanation:
- A dilation is a transformation that creates an image using a scale factor that has the exactly same shape as the original, but have a different size.
The given function :
We know that any function y= f(x) will become y=k f(x) after dilation of k units on the x, where k= scale factor for dilation.
Here, the given scale factor = 2 i.e. k=2
Then, the new function will be :
Hence, the new function is