1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
horrorfan [7]
3 years ago
13

The law of physics which states that energy can't be created or destroyed but can transfer or change forms is known as

Chemistry
2 answers:
Nat2105 [25]3 years ago
8 0
The law of conservation energy..
Sedaia [141]3 years ago
5 0
The Law of Conservation of Energy
You might be interested in
Step 5: Measure the Mass of the Water (Iron)
Ede4ka [16]

Answer:

12.42 g

Explanation:

because I saw your laptop so it is

7 0
1 year ago
What properties of matter are intensive independent of their size
Paha777 [63]

Answer:

temperature, refractive index, density, and hardness of an object

Explanation:

it is a bulk property, meaning that it is a physical property of a system that does not depend on the system size or the amount of material in the system

8 0
3 years ago
Camphor, a white solid with a pleasant odor, is extracted from the roots, branches, and trunk of the camphor tree. Assume you di
katrin [286]

<u>Answer:</u> The molarity of solution is 0.799 M , molality of solution is 1.02 m, mole fraction of camphor is 0.045 and mass percent of camphor in solution is 13.43 %

<u>Explanation:</u>

  • <u>Calculating the molarity of solution:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of camphor = 70.0 g

Molar mass of camphor = 152.2 g/mol

Volume of solution = 575 mL

Putting values in above equation, we get:

\text{Molarity of camphor}=\frac{70\times 1000}{152.2\times 575}\\\\\text{Molarity of camphor}=0.799M

  • <u>Calculating the molarity of solution:</u>

To calculate the mass of ethanol, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of ethanol = 0.785 g/mL

Volume of ethanol = 575 mL

Putting values in above equation, we get:

0.785g/mL=\frac{\text{Mass of ethanol}}{575mL}\\\\\text{Mass of ethanol}=(0.785g/mL\times 575mL)=451.38g

To calculate the molality of solution, we use the equation:

\text{Molality of solution}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

m_{solute} = Given mass of solute (camphor) = 70 g

M_{solute} = Molar mass of solute (camphor) = 152.2  g/mol

W_{solvent} = Mass of solvent (ethanol) = 451.38 g

Putting values in above equation, we get:

\text{Molality of camphor}=\frac{70\times 1000}{152.2\times 451.38}\\\\\text{Molality of camphor}=1.02m

  • <u>Calculating the mole fraction of camphor:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

<u>For camphor:</u>

Given mass of camphor = 70 g

Molar mass of camphor = 152.2 g/mol

Putting values in equation 1, we get:

\text{Moles of camphor}=\frac{70g}{152.2g/mol}=0.459mol

<u>For ethanol:</u>

Given mass of ethanol = 451.38 g

Molar mass of ethanol = 46 g/mol

Putting values in equation 1, we get:

\text{Moles of ethanol}=\frac{451.38g}{46g/mol}=9.813mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

Moles of camphor = 0.459 moles

Total moles = [0.459 + 9.813] = 10.272 moles

Putting values in above equation, we get:

\chi_{(camphor)}=\frac{0.459}{10.272}=0.045\

  • <u>Calculating the mass percent of camphor:</u>

To calculate the mass percentage of camphor in solution, we use the equation:

\text{Mass percent of camphor}=\frac{\text{Mass of camphor}}{\text{Mass of solution}}\times 100

Mass of camphor = 70 g

Mass of solution = [70 + 451.38] = 521.38 g

Putting values in above equation, we get:

\text{Mass percent of camphor}=\frac{70g}{521.38g}\times 100=13.43\%

Hence, the molarity of solution is 0.799 M , molality of solution is 1.02 m, mole fraction of camphor is 0.045 and mass percent of camphor in solution is 13.43 %

3 0
3 years ago
Why do magnesium, phosphorus, and zinc exhibit slightly higher first ionization energies than the general trend within each of t
Lapatulllka [165]
Because they are farther across the periodic table<span />
8 0
3 years ago
SOLUBILITY RULES: please help me with 2a-d
Sedbober [7]
A. K+, OH-
B. C6H5CO+, OH-
C. NH4+, Cl-
D. Mg++, 2 NO3-

Everything has 1 except for the Nitrate ion in D, which has 2
5 0
3 years ago
Other questions:
  • Why students should join in medical clubs?
    15·2 answers
  • When 0.103 g of Zn (s) is combined with enough HCl to make 50.0 mL of solution in a coffee cup calorimeter, all of the zinc reac
    13·1 answer
  • Hydrogen bonds can be found between molecules of which substance? NH3 H2 HI CH4
    6·1 answer
  • Which describes Bohr’s contribution to the atomic model?
    7·1 answer
  • How might you make sure you have the correct amount of nitrogen and hydrogen so that you have enough of each with not wasted sur
    10·1 answer
  • How many moles of SnF₂ will be produced along with 48 grams of H₂?
    5·1 answer
  • The number 0.0007270 is larger than the number 5.7 × 10–3.
    15·1 answer
  • Ocean water is a combination of salt and water. Which of the following best describes the composition of ocean water? It is an e
    5·1 answer
  • Arrange the isotopes of chlorine and sulfur in order of decreasing number of neutrons. Rank the isotopes from most to fewest neu
    5·1 answer
  • Suggest two materials produced from hydrocarbons by the petrochemical industry.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!