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Alexxandr [17]
3 years ago
10

write a rule that could be used to find the distance from any positive number to any negative number.

Mathematics
1 answer:
hram777 [196]3 years ago
3 0

Answer:

not sure but i think it is

+ × + = +

- × - = +

- × + = +

+ ×- = -

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Steps to solve<br>1/2 / 2/-5 + (-1/4)​
NARA [144]

Answer:

-3/2

Step-by-step explanation:

this is a answer first u dived then plus

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3 years ago
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If f(x) = kx^3+ x^2 − kx + 2, find a number k such that the graph of f contains the point (k, -10)
Elina [12.6K]

If we write k where we see x in the equation and set the result equal to -10, we get the result.

  • f(k)=k(k)^3+k^2-k(k)+2
  • =k^4+k^2-k^2+2
  • =k^4+2=-10
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1 year ago
What is minus 6 plus 2?<br><br><br> -4<br><br><br> 8<br><br><br> 4
schepotkina [342]

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Step-by-step explanation:

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3 0
3 years ago
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Can you help me find this answer<br><br>​
IRISSAK [1]

Answer:

a= 18 girls in the class, b= 20 boys and 15 girls, 12 oranges better price.

Step-by-step explanation:

for question a, there are 18 girls in the class, this is how i worked it out:

the ratio of boys to girls is 4:3.

there are 24 boys.

24 is 6 times more than 4.

if boys are 6 times more than the original ratio, we also have to times the amount of girls by 6.

6x3= 18.

for question b i got 20 boys and 15 girls, this is how i did it.

there are 35 students in total.

4:3= boys to girls.

4+3=7

7 goes into 35 five times.

ratio of boys to girls is 4:3 so 5x4 for boys = 20 and 3x5 for girls = 15.

answer= 20 boys and 15 girls.

12 oranges is a better deal, this is how i worked it out.

it is 60 for 12 oranges.

it is 48 for 8 oranges.

12x5= 60 , 8x6=48.

you only have to times 12 by 5 to get it to the price but you have to times 8 by 6 to get it to the price, proving that 12 oranges for 60 is a better deal.

5 0
3 years ago
A. What is the perimeter of the rectangle?<br> B. What is the area of the rectangle?
Archy [21]

Answer:

A) perimeter = 3 + 3 + 8 + 8 = 22 units

B) area = 3 x 8 = 24 units²

Step-by-step explanation:

4 0
2 years ago
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