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sineoko [7]
3 years ago
15

Nancy drives 624 miles in 10 hours, driving the same number of miles each hour. Rebecca drives 660 miles in 12 hours, driving th

e same number of miles each hour. Which statement correctly compares the number of miles per hour they drove
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Which statements are true about the ordered pair  <span>(−1, 5)</span> and the system of equations?

<span>{<span><span>x+y=4          </span><span>x−y=−6</span></span></span>

Select each correct answer.

<span>The ordered pair  <span>(−1, 5)</span> is a solution to the first equation because it makes the first equation true.The ordered pair  <span>(−1, 5)</span> is a solution to the second equation because it makes the second equation true.The ordered pair  <span>(−1, 5)</span> is not a solution to the system because it makes at least one of the equations false.The ordered pair  <span>(−1, 5)</span> is a solution to the system because it makes both </span>
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Calculate the value of b + 12.5=12
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Answer:

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Step-by-step explanation:

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3 years ago
Change the following fractions into mixed numbers
Travka [436]
A) 23/8 divide 23 by 8 to get 2 with remainder 7 therefore 2 7/8
work all by treating each fraction as a division problem and placing the remainder over the divisor 
b) 14/3 = 4 2/3
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6 0
3 years ago
Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any
alukav5142 [94]

Answer:

y(x)=4+\frac{C}{\sqrt{x^2+10}}

Step-by-step explanation:

We are given that a differential equation

(x^2+10)y'+xy-4x=0

We have to find the general solution of given differential equation

y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0

y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}

Compare with

y'+P(x) y=Q(x)

We get

P(x)=\frac{x}{x^2+10}

Q(x)=\frac{4x}{x^2+10}

I.F=e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}

e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}

y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C

y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C

y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C

y(x)=4+\frac{C}{\sqrt{x^2+10}}

6 0
3 years ago
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