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3 years ago

What do proteins and nucleus acids have in common

Chemistry

1 answer:

Harrizon [31]3 years ago

5 0

Answer:

They are both polymers that are found in living cells.

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The table below gives some characteristics of element Y. Characteristics of element Y Values Mass number 11 Number of neutrons i

Elden [556K]

I believe the answer is Na because it should be sodium which is Na.

6 0

3 years ago

Read 2 more answers

Which name is associated with a system of climate zones?

andrew11 [14]

Answer: A. Wladimir Koppen.

I hope that this helps you and good luck!!

~Sara

8 0

3 years ago

How do the percent compositions for C3H6 and C4H7 compare?

mariarad [96]

A. They are the same

<h3>Further explanation</h3>

Given

C3H6 and C4H8

Required

The percent compositions

Solution

C₃H₆(MW = 42 g/mol)

%C = 3.12/42 x 100% = 85.71%

%H = 6.1/42 x 1005 = 14.29%

C₄H₈(MW=56 g/mol)

%C = 4.12/56 x 100% = 85.71%

%H = 8.1/56 x 100%=14.29%

So they are the same, because mol ratio of C and H in both compounds is the same, 1: 2

3 0

3 years ago

Xcc of 5N HCL was diluted to 1 litre of normal solution calculate the value of x

Colt1911 [192]

Answer:

200cc of 5N HCl were diluted

Explanation:n

<em>Assuming the solution was diluted to prepare a 1N HCl solution:</em>

The HCl was diluted from 5N to 1N, that is a dilution of:

5N / 1N = 5 times

As the total volume of the diluted solution is 1L = 1000mL = 1000cc the amount of the concentrated solution was:

1000cc / 5 =

<h3>200cc of 5N HCl were diluted</h3>

7 0

3 years ago

Consider a transition of the electron in the hydrogen atom from n=3 to n=7.

kow [346]

<u>Answer:</u>

<u>For a:</u> The wavelength of light is $1.005\times 10^{-6}m$

<u>For b:</u> The light is getting absorbed

<u>Explanation:</u>

<u>For a:</u>

To calculate the wavelength of light, we use Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $1.097\times 10^7m^{-1}$

$n_f$ = Higher energy level = 7

$n_i$ = Lower energy level = 3

Putting the values in above equation, we get:

$\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{3^2}-\frac{1}{7^2} \right )\\\\\lambda =1.005\times 10^{-6}m$

Hence, the wavelength of light is $1.005\times 10^{-6}m$

<u>For b:</u>

There are two ways in which electrons can transition between energy levels:

<u>Absorption spectra:</u> This type of spectra is seen when an electron jumps from lower energy level to higher energy level. In this process, energy is absorbed.
<u>Emission spectra:</u> This type of spectra is seen when an electron jumps from higher energy level to lower energy level. In this process, energy is released in the form of photons.

As, the electron jumps from lower energy level to higher energy level. The wavelength is getting absorbed.

6 0

4 years ago