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Nitella [24]
3 years ago
8

In an ionic bond:

Chemistry
2 answers:
Charra [1.4K]3 years ago
5 0

Answer:

One atom accepts electrons from another.

Explanation:

Answer via Educere/ Founder's Education

xz_007 [3.2K]3 years ago
3 0
The answer I'm pretty sure is a because it can't be d because ionic binding the electrons are affected and it can't be c because that's covalent bonding and it can't be b because they don't swap electrons.
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Which compound contains both ionic and covalent
musickatia [10]

Answer:

(3) NaNO₃

Step-by-step explanation:

Sodium nitrate has ionic bonds, because it consists of Na⁺ and NO₃⁻ ions.

However, the nitrate ions have <em>covalent bonds</em> between the O atoms and the central N atoms.

(1) and (2) are <em>wrong</em>. Both N₂O₅ and HCl consist of nonmetals, so they are <em>covalent</em> compounds.

(4) is <em>wrong</em>. NaCl has <em>only ionic bonds</em> between the Na⁺ and Cl⁻ ions

7 0
3 years ago
Read 2 more answers
What is required to move from one state or phase of matter to the next
tigry1 [53]

energy is required to move from one state or phase of matter to the next. Energy is used to make a liquid into a gas or a solid into a liquid.

7 0
3 years ago
What is an ionic bond
Pani-rosa [81]
Ionic bonding is the complete transfer of valence electron(s) between atoms. It is a type of chemical bond that generates two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.
7 0
3 years ago
Read 2 more answers
At STP how many moles or helium would occupy a volume of 12 liters?
butalik [34]
1 mole ------------- 22.4 L ( at STP )
?? mole ---------- 12 L

12 x 1 / 22.4 => 0.5357 moles

hope this helps! 
5 0
4 years ago
Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s
Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

                        N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

where N is amount of radioactive nuclide after t time, N_{0} is initial amount of radioactive nuclide and t_{\frac{1}{2}} is half life of radioactive nuclide

Here N_{0}=4.60 mg, t=4.1\times 10^{9}yr and t_{\frac{1}{2}}=4.5\times 10^{9}yr

So,N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}

so, N = 2.446 mg

mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg

3 0
3 years ago
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