1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Over [174]
4 years ago
13

"a uniform thin rod of length 0.962 m is hung from a horizontal nail passing through a small hole in the rod located 0.048 m fro

m the rod's end. when the rod is set swinging about the nail at small amplitude, what is the period of oscillation?"
Physics
1 answer:
exis [7]4 years ago
5 0
<span>1.57 seconds. The rod hanging from the nail constructs a physical pendulum. The period of such a pendulum follows the formula T = 2*pi*sqrt(L/g) where T = time L = length of pendulum g = local gravitational acceleration So the problem becomes one of determining L. It's tempting to consider L to be the distance between the center of mass and the pivot, but that isn't the right value. The correct value is the distance between the pivot and the center of percussion. So let's determine what that is. We can treat the uniform thin rod as an uniform beam and for an uniform beam the distance between the center of mass and the center of percussion is expressed as b = L^2/(12A) where b = distance between center of mass and center of percussion L = length of beam A = distance between pivot and center of mass Since the rod is uniform, the CoM will be midway from either end, or 0.962 m / 2 = 0.481 m from the end. The pivot will therefore be 0.481 m - 0.048 m = 0.433 m from the CoM Now let's calculate the distance the CoP will be from the CoM: b = L^2/(12A) b = (0.962 m)^2/(12 * 0.433 m) b = (0.925444 m^2)/(5.196 m) b = 0.178107005 m With the distance between the CoM and CoP known, we can now calculate the effective length of the pendulum. So: 0.433 m + 0.178107005 m = 0.611107005 m And finally, with the effective length known, let's calculate the period. T = 2*pi*sqrt(L/g) T = 2*pi*sqrt((0.611107005 m)/(9.8 m/s^2)) T = 2*pi*sqrt(0.062357858 s^2) T = 2*pi*0.249715554 s T = 1.569009097 s Rounding to 3 significant figures gives 1.57 seconds. Let's check if this result is sane. Looking up "Seconds Pendulum", I get a length of 0.994 meters which is longer than the length of 0.611 meters calculated. But upon looking closer at the "Seconds Pendulum", you'll realize that it's period is actually 2 seconds, or 1 second per swing. So the length of the calculated pendulum is sane.</span>
You might be interested in
In a material for which o=5.0 S/m and e, =1 the electric field intensity is E- 250 sin 10" (V/m). Find the conduction and displa
Elodia [21]

Answer:

Explanation:

Given that:

The conductivity of the material \sigma = 5.0 s/m

The  \ relative  \ permittivity \  of \  the \  material {\varepsilon_r} = 1 ; &

The electric field intensity of the material E = 250 sin(10¹⁰ t) V/m

(a) The conduction current density ( J_c) = \sigma E

= 5.0 \times 250 \ sin ( 10^{10} \ t )

\mathbf{ = 1250 \ sin (10 ^{10} t ) \ A/m^2 }

(b)  Displacement  current density (J_d) = \varepsilon _d * \dfrac{\delta E}{\delta t}

Recall that:

\varepsilon _o  = 8.854 \times 10^{-12}

∴

(J_d) =  8.854 \times 10^{-12} \times \dfrac{d}{dt} \times  (250  \ sin \ (10^{10} \ t))

(J_d) = 8.854 \times 10^{-12} \times 250 \times 10^{10} \times \ cos \ (10^{10} \ t)

(J_d) = 22.135 \ cos \  10^{10} \ t \ A/m^2

(c) The frequency at which J_c  \  and  \  J_d will have the same magnitude is:

f = \dfrac{\sigma}{2 \pi \varepsilon_o \varepsilon_r}

By substitution

f = 18 \times 10^9 \times \dfrac{\sigma }{\varepsilon_r}

f = 18\times 10^9 \times \dfrac{5}{1 }

f = 90 GHz

5 0
3 years ago
The formula Sequals16tsquared is used to approximate the distance​ S, in​ feet, that an object falls freely from rest in t secon
Tom [10]

S = 16t² where t = time in seconds.

Let S = 1190ft then solve for t:

16t² = 1190

t² = 74.4

t = 8.62s

5 0
3 years ago
A jogger runs 5.0 km on a straight trail at an angle of 60° south of west. What is the southern component of the run rounded to
geniusboy [140]

Answer:

4.3 km

Explanation:

5 0
2 years ago
Heinrich hertz used properties of which type of wave to support the idea that light is also made of waves?.
Vsevolod [243]

Answer:

Hertz extended Maxwell's idea that light is produced by the interaction of electromagnetic fields. Waves produced a diffraction pattern. Results supported the wave theory of light.

7 0
2 years ago
Read 2 more answers
The frequency of a sound wave in water is 15,000 Hz, and the sound wave travels through water at a speed of 1,500 m/s. What is t
motikmotik
I think the answer would be 150 m/s
8 0
3 years ago
Other questions:
  • A forest fire wipes out all of the plant life in an area, causing the animals to leave. The ground becomes a mixture of soil and
    8·2 answers
  • During a severe storm, electrical transformers that function independently are expected to operate 85 percent of the time. Suppo
    11·1 answer
  • Car decelerates uniformly and comes to a stop after 10 s. The car's average velocity during deceleration was 50 km/h. What was t
    15·1 answer
  • A balloon will stick to a wooden wall if the balloon is charged
    5·1 answer
  • Upon which one of the following parameters does the energy of a photon depend? A. Mass B. Amplitude C. Polarization D. Frequency
    13·1 answer
  • A bus moving on a straight road increases its speed uniformly from rest to 20m's over a time period of 1 min. The distance trave
    13·1 answer
  • Is cereal a soup? aCTUALLY EXPLAIN WHY OR WHY NOT!
    5·1 answer
  • If you added enough ropes and pulleys to lift any size mass would it be possible to never have to apply a force to move your mas
    5·2 answers
  • Can someone please answer this, ill give you brainliest Would be very appreciated.
    12·1 answer
  • A ball is projected with initial velocity 50m/s at an angle of elevation of 37 degrees from the top of a cliff 55 m high. Calcul
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!