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vazorg [7]
3 years ago
13

What are the two types of electrical circuits

Physics
2 answers:
Bezzdna [24]3 years ago
8 0

Answer:series circuit and parallel circuit

Explanation:

There two types of circuit are series circuit and parallel circuit

uysha [10]3 years ago
3 0

Series Circuit
A series circuit there is only one path for the electrons to flow (see image of series circuit). The main disadvantage of a series circuit is that if there is a break in the circuit the entire circuit is open and no current will flow. An example of a series would the the lights on many inexpensive Christmas trees. If one light goes out all of them will.



Parallel Circuit
In a parallel circuit the different parts of the electric circuit are on several different branches. There are several different paths that electrons can flow. If there is a break in one branch of the circuit electrons can still flow in other branches (see image of parallel circuit). Your home is wired in a parallel circuit so if one light bulb goes out the other will stay on.





HOPE THIS HELPS YOU MATE!!
I HAVE ALSO GIVEN THE EXPLANATION THINKING THAT IT MIGHT HELP YOU.
THANK YOU.
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The best answer is b - span.

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There are many kinds of bridges  but they all fall into three types namely beam, arch and suspension. The major difference between these three kinds of bridges is the distance that each can cross in  a single span.

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5 0
3 years ago
If sunlight begins to warm a frozen lake, the atoms in the lakes frozen water will begin to move faster. True of False?
Vinvika [58]
True, the water would eventually move from solid back to liquid form because of the heat.<span />
4 0
3 years ago
A tool for studying motion is called?
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phytochemical

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8 0
3 years ago
A single slit 1.4 mmmm wide is illuminated by 460-nmnm light. Part A What is the width of the central maximum (in cmcm ) in the
mamaluj [8]

Answer:

<h2> 1.643*10⁻⁴cm</h2>

Explanation:

In a single slit experiment, the distance on a screen from the centre point is expressed as y = \frac{\delta m \lambda d}{a} where;

\delta m is the first two diffraction minima = 1

\lambda is light wavelength

d is the distance of diffraction pattern from the screen

a is the width of the slit

Given \lambda = 460-nm = 460*10⁻⁹m

d = 5.0mm = 5*10⁻³m

a = 1.4mm = 1.4*10⁻³m

Substituting this values into the formula above to get width of the central maximum y;

y = 1*460*10⁻⁹ * 5*10⁻³/1.4*10⁻³

y = 2300*10⁻¹²/1.4*10⁻³

y = 1642.86*10⁻⁹

y = 1.643*10⁻⁶m

Converting the final value to cm,

since 100cm = 1m

x = 1.643*10⁻⁶m

x = 1.643*10⁻⁶ * 100

x = 1.643*10⁻⁴cm

Hence, the width of the central maximum in the diffraction pattern on a screen 5.0 mm away is  1.643*10⁻⁴cm

3 0
3 years ago
An electric pole casts a shadow of 24 m long . If the tip of the shadow is 25m far from the top of the pole , how high is the po
Vikentia [17]

Answer:

7 m

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a^ + b^=c^

a^ + 24^=25^

a^+576=625

a^=625-576

a^=49

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7 0
3 years ago
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