Answer:
C)You should use the thin cooking twine.
Explanation:
A)You can choose either because they are the same length and will produce the same wave speed.
B)You should use the heavy rope.
C)You should use the thin cooking twine.
The speed of wave in a string is given by the following formula:
|
| = 
Where || = speed of wave, 
= tension in the string, and μ = mass per length of the string.
<em>Even though the two strings have the same length, the μ (mass/length) for the heavy rope will be more than the that of a thin rope. Consequently, the </em><em>:μ for the thin rope will be higher than that of the heavy rope and as such, gives a bigger |</em><em>|. </em>
Therefore, the thin rope should be used in order to get a faster wave speed in the telephone.
The correct option is C.
Answer:
<h2>3 m/s^2</h2>
Explanation:
Step one:
given
Mass m= 4kg
Force F= 12N
Required
Acceleration the relation between force, acceleration, and mass is Newton's first equation of motion, which says a body will continue to be at rest or uniform motion unless acted upon by an external force
F=ma
a=F/m
a=12/4
a=3 m/s^2
Answer:
C2, C1, C4, C5 and C6 are in parallel. Therefore, we use the formula Cp = C1 + C2 + ....
Cp = C2 + C1 + C4 + C5 + C6 = ( 7 * 10 ^-3) + (18 * 10^-6) + (0.8F) + (200 * 10^-3 F) + (750 * 10^-6) = 1.008F
Now, Cp will become one capacitor and it will be aligned with C3, therefore it will now become a circuit in series.
We use the formula: 1/Cs = 1/C1 + 1/C2 + .... + ....1/Cn
Thus,
1/Cs = 1/C3 + 1/Cp
1/Cs = 1/(14 * 10^-3 F) + 1/(1.008F)
Cs = 1.4 * 10 ^-2 or if we do not round too much it will give exactly 0.0138 F
So the answer should be a)
<span>speed = wavelength x frequency
speed = 0.4m X 10 Hz
speed = 4 m/s</span>
