Factorise 3(2x + 3y)^2 - 8x - 12y
First, we FOIL it.
FOIL: First, Outside, Inside, and Last
(2x + 3y)(2x + 3y)
First: 2x*2x = 4x^2
Outside: 2x*3y = 6xy
Inside: 3y*2x = 6xy
Last: 3y*3y = 9y^2
Before, we move on, we have to combine any like terms.
6xy + 6xy = 12xy
Then, when we've finished FOILing it, we place a pair of parentheses around these.
3 (9y^2 + 4x^2 + 12xy) -8x - 12y
Now, we can distribute the 3.
3 * 9y^2 = 27y^2
3 * 4x^2 = 12x^2
3 * 12xy = 36xy
Lastly, we combine any like terms if there are any.
Expression: 27y^2 + 12^2 + 36xy - 8x - 12y
None of these all have a greatest common factor for the whole set.
So, therefore, the factorised form of 3(2x + 3y)^2 - 8x - 12y is:
27y^2 + 12x^2 + 36xy - 8x - 12y
The sum of the acute angles in a right triangle is 90°.
Therefore we have the equation:
x° + 2x° = 90°
3x° = 90° <em>divide both sides by 3</em>
x° = 30°
<h3>Answer: x = 30</h3>
Answer:
a) = 4/9 b) -20/21
c) -77/6 d) 39/22
Step-by-step explanation:
8,3 and 5 would be my guess
