Answer:
See explanation
Explanation:
This conversion must go through a sequence of steps as i have shown in the image attached to this answer.
The acetone is converted to propan-2-ol using LiAlH4, THF and acid. The propan-2-ol may be converted to propene by E2 elimination. Addition of HBr yields 2-bromo propane.
The Wurtz reaction converts 2-bromo propane to 2,3- dimethyl butane. This can be brominated in the presence of light to yield 3-bromo-2,3-dimethyl butane. Elimination of HBr using a base leads to the formation of the required product as shown.
Answer:
d. To the left because Q > K_p
Explanation:
Hello,
In this case, for the given reaction:
The pressure-based equilibrium expression is:
In such a way, since Kp is given we rather compute the reaction quotient at the specificed pressure of carbon dioxide as shown below:
Therefore, since Q>Kp we can see that there are more products than reactants, which means that the reaction must shift leftwards towards the reactants in order to reestablish equilibrium, thus, answer is d. To the left because Q > Kp.
Regards.
<u>Answer:</u> Aluminium is getting oxidized in the given chemical reaction.
<u>Explanation:</u>
Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.
Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.
For the given chemical reaction:
The half cell reactions for the above reaction follows:
<u>Oxidation half reaction:</u>
<u>Reduction half reaction:</u>
As, aluminium is loosing 3 electrons to form aluminium cation. Thus, it is getting oxidized. Iron is gaining 2 electrons to form iron anion. Thus, it is getting reduced.
Hence, the oxidized species of the given reaction is aluminium.