Answer:
5.3 × 10⁻³ kg
Explanation:
There is some info missing. I think this is the original question.
<em>A chemist adds 135.0 mL of a 0.21 M zinc nitrate (Zn(NO₃)₂) solution to a reaction flask. Calculate the mass in kilograms of zinc nitrate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.</em>
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We have 135.0 mL of a 0.21 M zinc nitrate (Zn(NO₃)₂) solution. The moles of zinc nitrate are:
0.1350 L × 0.21 mol/L = 2.8 × 10⁻² mol
The molar mass of zinc nitrate is 189.36 g/mol. The mass corresponding to 2.8 × 10⁻² moles is:
2.8 × 10⁻² mol × 189.36 g/mol = 5.3 g
1 kilogram is equal to 1000 grams. Then,
5.3 g × (1 kg/1000 g) = 5.3 × 10⁻³ kg
Answer:
The solutions of hydrobromic acid and of chloric acid are the most electrically conductive.
Explanation:
The electrical conductivity of a solution is determined by the concentration of ions in the solution. The acids listed react with water to form ions. In the case of hydrobromic acid, for example, the reaction is as follows:
HBr + H2O >> H3O(+) + Br(-)
Hydrobromic acid and chloric acid are strong acids, meaning the reaction is considered to proceed at 100%. Acetic acid, however, is a weak acid and the reaction with water does not go to completion, so there are less ionic species in the solution of acetic acid, which makes it less electrically conductive.
Answer:
Well why didn't you do it? Have a great day and I am so sorry for wasting your points I don't need them. I hope someone helps!! ;)
Explanation:
