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3 years ago

Write the balanced molecular chemical equation for the reaction

2 answers:

4 0

The balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

For any chemical equation to be balanced, the number of moles of elements in the reactants must be equal to that of the product.

According to the question, we are to write a balanced equation for the reaction in aqueous solution for cesium carbonate and magnesium nitrate

The chemical formula for Cesium carbonate is Cs₂CO₃

The chemical formula for magnesium nitrate is Mg(NO₃)₂

Hence the balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

Learn more here: brainly.com/question/11904811

vfiekz [6]3 years ago

3 0

Answer:

Cs2CO3 + Mg(NO3)2 -> 2CsNO3 + MgCO3

Explanation:

This is a typical double displacement equation, and balancing this equation by adding the 2 in front of the cesium would solve this problem.

The answer in words would be :

Cesium Carbonate + Magnesium Nitrate = Cesium Nitrate + Magnesite.

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4 years ago

Does anybody know this also explain

Tresset [83]

Answer:

brainliest answer

I believe this is correct

Explanation:

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3 years ago

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nexus9112 [7]

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4 years ago

Read 2 more answers

A 25 kg rock is placed in a graduated cylinder with water.the volume of the fluid is 18.3ml.calculate the density of the rock in

ipn [44]

Answer:

=> 1366.120 g/mL.

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m) = 25 Kg

Volume (v) = 18.3 mL.

From our question, we are to determine the density (rho) of the rock.

The formula:

$p = \frac{m}{v}$

First let's convert 25 Kg to g;

1 Kg = 1000 g

25 Kg = ?

$= \frac{25 × 1000}{1}$

= 25000 g

Substitute the values into the formula:

$p = \frac{25000 g}{18.3 ml}$

= 1366.120 g/mL.

Therefore, the density (rho) of the rock is 1366.120 g/mL.

8 0

2 years ago

The standard Gibbs energy of reaction, ÄG°, for the dissociation of phenol is 56.4 kJ mol-1 at 298 K. Calculate the pKa of pheno

Neporo4naja [7]

Answer:

9.88

Explanation:

ΔG = - 2.303 RT log Ka

ΔG is change in free energy at temperature T , Ka is equilibrium constant

- 56.4 x 10³ = 2.303 x 8.31 x 298 logKa

- log Ka = 9.88 .

pKa = 9.88 .

4 0

3 years ago