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3 years ago

Write the balanced molecular chemical equation for the reaction

2 answers:

4 0

The balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

For any chemical equation to be balanced, the number of moles of elements in the reactants must be equal to that of the product.

According to the question, we are to write a balanced equation for the reaction in aqueous solution for cesium carbonate and magnesium nitrate

The chemical formula for Cesium carbonate is Cs₂CO₃

The chemical formula for magnesium nitrate is Mg(NO₃)₂

Hence the balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

Learn more here: brainly.com/question/11904811

vfiekz [6]3 years ago

3 0

Answer:

Cs2CO3 + Mg(NO3)2 -> 2CsNO3 + MgCO3

Explanation:

This is a typical double displacement equation, and balancing this equation by adding the 2 in front of the cesium would solve this problem.

The answer in words would be :

Cesium Carbonate + Magnesium Nitrate = Cesium Nitrate + Magnesite.

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In the laboratory you dissolve 22.8 g of chromium(III) acetate in a volumetric flask and add water to a total volume of 250 mL.

IRINA_888 [86]

Answer:

The molarity of the chromium(III) acetate solution 0.3982 M.

0.3982 M is the concentration of the chromium(III) cation.

1.1946 M is the concentration of the acetate anion.

Explanation:

$Molarity=\frac{\text{Mass of substance}}{\text{Molar mass of substance}\times \text{Volume of solution(L)}}$

Mass of chromium(III) acetate = 22.8 g

Molar mass of chromium(III) acetate = 229 g/mol

Total volume of the solution of chromium(III) acetate = V = 250 mL = 0.250 L

1 mL = 0.001 L

The molarity of the chromium(III) acetate solution :

$[Cr(CH_3COO)_3]=\frac{22.8 g}{229 g/mol\times 0.250 L}=0.3982 M$

The molarity of the chromium(III) acetate solution 0.3982 M.

$Cr(CH_3COO)_3\rightarrow Cr^{3+}+3CH_3COO^-$

According to reaction, 1 mole of chromium(III) acetate gives 1 mole of chromium(III) ions and 3 moles of acetate ions.

So $[Cr^{3+}]=[Cr(CH_3COO)_3]=0.3982 M$

$[CH_3COO^-]=3\times [Cr(CH_3COO)_3]=3\times 0.3892 M=1.1946 M$

0.3982 M is the concentration of the chromium(III) cation.

1.1946 M is the concentration of the acetate anion.

5 0

3 years ago

A sample of C3H8 has 3.20 × 1024 H atoms. How many carbon atoms does the sample contain? What is the total mass of the sample in

guajiro [1.7K]

<span>A sample of C3H8 has 3.20 × 10^24 H atoms.

We will use Avogadro's number for this problem. Avogadro's number states that there are 6.022x 10^23 atoms per mole of a substance. We will use dimensional analysis, notice how the units cancel in the computation below:

</span>3.20 × 10^24 atoms H * (1 mole H/6.022x 10^23 atoms H) * (3 moles C/8 moles H) * (6.022x 10^23 atoms C/1 mole C) = 1.2 x 10^24 atoms C

To get the total mass of the sample in grams, let us note that there are 3 moles of carbon and 8 moles of hydrogen per mole of C3H8, and using the molecular weights of C (12 g/mol) and H (1 g/mol), we get (12*3)+(1*8)= 44 g/mol as the molar mass.

3.20 × 10^24 atoms H * (1 mole H/6.022x 10^23 atoms H) * (1 mole C3H8/8 moles H) * (44 g C3H8 / 1 mole C3H8) = 29.23 g C3H8<span>

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3 years ago