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crimeas [40]
3 years ago
12

Describe how you would create a model of sea-floor spreading using everyday materials

Chemistry
1 answer:
Elodia [21]3 years ago
4 0

Answer:

Take a cardboard, cylinder-shaped container and cut a vertical slit about 3 ½ inches long and ¼ inch wide down the side. The slit is your mid-ocean ridge, the place where the plates are moving away from each other.

Cut a piece of white paper in half lengthwise.

On each piece of paper, measure two inches in from the end and fold the paper so that there is a section on each end to hold onto.

Measure inward another two inches from the fold, and color in that two-inch wide strip.

Continue to measure in two-inch segments, coloring every other section.

Place the unfolded ends of the paper into the slit in the container. Holding them by the folds, pull the pieces of paper out again. If you imagine that the slit is the midocean ridge where the plates are moving away from each other, the paper is the new liquid rock coming out from the ridge. The first bit of paper to come out is the oldest rock, and the last section of paper to come out is the youngest. Imagine that your paper goes on forever. Soon, the first bit you took out of the hole will be far away from the midocean ridge. Of course, “soon” in geological time is a very long time in human terms!

Take your pieces of paper and tape the ends that aren’t folded to the pencil.

Put the pencil inside of the container and pull the ends of the pieces of paper up through the slit.

Twist the pencil one way, and the papers will move out and away from each other. This is what happens at a divergent plate boundary on the mid-ocean ridges.

Twist the pencil the other way, and the papers will move in and toward each other. This is what happens at a convergent plate boundary. Imagine what would happen if those papers had bumps on them. They’d get all bunched together at the hole, and create mountains.

Explanation:

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5 0
3 years ago
Which of the following equations are balanced?
Law Incorporation [45]
A: 2H₂ + O₂ → 2H₂O

    H: 4            H:4
    O: 2           O: 2

The equation is balanced.

B. 2S + 3O₂ → 2SO₃

     S: 2             S: 2
     O: 6            O: 6

The equation is balanced.

C. Li + Cl₂ → LiCl

     Li: 1          Li: 1
    Cl: 2          Cl: 1

The equation is not balanced.

    2Li + Cl₂ → 2LiCl

    Li: 2            Li: 2
    Cl: 2           Cl: 2

D: 2K + 2H₂O → H₂ + 2KOH

    K: 2                 K: 2
    H: 4                 H: 4
    O: 2                 O: 2

The equation is balanced.

E: 2Fe + Cu(NO₃)₂ → 2Cu + Fe(NO₃)₂

    Fe: 2                       Fe: 1
    Cu: 1                      Cu: 2
      N: 2                        N: 2
      O: 6                        O: 6

The equation is not balanced.

2Fe + 2Cu(NO₃)₂ → 2Cu + 2Fe(NO₃)₂

Fe: 2                        Fe: 2
Cu: 2                       Cu: 2
  N: 4                         N: 4
  O: 12                       O: 12

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The bottom of the food chain
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The half-life of argon-39 is 269 years. It decays into krypton-39. After 1,076 years, what fraction of the original amount of ar
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Answer:

1/16

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 269 years

Time (t) = 1076 years

Fraction remaining =?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Half-life (t½) = 269 years

Time (t) = 1076 years

Number of half-lives (n) =?

n = t / t½

n = 1076 / 269

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the fraction of the original amount remaining. This can be obtained as follow:

Let N₀ be the original amount.

Let N be the amount remaining.

Number of half-lives (n) = 4

Fraction remaining (N/N₀ ) =?

N = 1/2ⁿ × N₀

N = 1/2⁴ × N₀

N = 1/16 × N₀

Divide both side by N₀

N/N₀ = 1/16

Thus, the fraction of the original amount remaining is 1/16

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Neutron or neutral and electran are positive
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