3ch4o number of atoms
1 answer:
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Answer:
V₂ = 0.4 L
Explanation:
<u>Data:</u>
- P₁ (initial pressure) = 500 torr
- V₁ (initial volume) = 0.5 L
- P₂ (final pressure) = 700 torr
<u>Wanted:</u>
- V₂ (final volume)
<u>Equation:</u>
- P₁V₁ = P₂V₂ → V₂ = P₁V₁ / P₂
<u>Solution:</u>
- V₂ =
= 0.3571 L or 0.4 L
Answer:
Explanation:
Given parameters:
pH = 3.50
Unknown:
concentration of [H₃0⁺] = ?
concentration of [OH⁻] = ?
Solution:
In order to find the unknown, we use some simple expressions which best explains the pH scale and the equilibrium systems of aqueous solutions.
pH = -log₁₀[H₃O⁺]
[H₃O⁺] = inverse log₁₀ (-pH) = =
[H₃O⁺] = 3.2 x 10⁻⁴moldm⁻³
For the [OH⁻]:
we use : pOH = -log₁₀ [OH⁻]
Recall: pOH + pH = 14
pOH = 14 - pH = 14 - 3.5 = 10.5
Now we plug the value of pOH into pOH = -log₁₀ [OH⁻]
[OH⁻] =
[OH⁻] = = 3.2 x 10⁻¹¹moldm⁻³
The solution is acidic as the concentration of H₃0⁺ is more than that of the OH⁻ ions.