Answer:
Mass = 47.04 g
Volume = 23.94 L
Solution:
The equation for given reaction is as follow,
BaCO₃ + 2 HNO₃ → Ba(NO₃)₂ + CO₂ + H₂O
According to this equation,
197.34 g (1 mole) BaCO₃ produces = 44 g (1 mole) of CO₂
So,
211 g of BaCO₃ will produce = X g of CO₂
Solving for X,
X = (211 g × 44 g) ÷ 197.34 g
X = 47.04 g of CO₂
As we know,
44 g (1 mole) CO₂ at STP occupies = 22.4 L volume
So,
47.04 g of CO₂ will occupy = X L of Volume
Solving for X,
X = (47.04 g × 22.4 L) ÷ 44 g
X = 23.94 L Volume
Mathematical formula of Ideal Gas Law is PV=nRT
where: P-pressure,
V-volume
n-number of moles; m/MW
T-Temperature
m-mass
d-density ; m/V
MW-Molecular Weight
R- Ideal Gas constant. If the units of P,V,n & T are atm, L, mol & K respectively, the value of R is 0.0821 L x atm / K x mol
Substituting the definitions to the original Gas equation becomes:
d= P x MW / (RxT)
Solution : d= .90atm x 28 g/mol (CO) / 0.0821Lxatm / mol x K x 323 K
d = 25.2 g / 26000 mL
d = .0.00096 g/mL is the density of CO under the new conditions
D or A copy of the papers in my
The controlled variable is what he eats, the dependent variable is his weight.
a word of advice for your next ask, try to use better grammar and punctuation because this was kinda hard to follow.
