Answer:
49.09 moles of gas are added to the container
Explanation:
Step 1: Data given
Initial volume = 3.10 L
Number of moles gas = 9.51 moles
The final volume = 19.1 L
The pressure, temperature remain constant
Step 2: Calculate number of moles gas
V1/n1 = V2/n2
⇒with V1 = the initial volume of the gas = 3.10 L
⇒with n1 = the initial number of moles = 9.51 moles
⇒with V2 = the increased volume = 19.1 L
⇒with n2 = the final number of moles gas
3.10L / 9.51 moles = 19.1 L / n2
n2 = 58.6 moles
The new number of moles is 58.6
Step 3: calculate the number of moles gas added
Δn = 58.6 - 9.51 = 49.09 moles
49.09 moles of gas are added to the container
