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Lena [83]
3 years ago
15

The half-life of tritium (H-3) is 12.3 years. If 48.0mg of tritium is released from a nuclear power plant during the course of a

mishap, what mass of the nuclide will remain after 49.2 years?
Chemistry
1 answer:
Rudiy273 years ago
6 0

Answer:

The amount left after 49.2 years is 3mg.

Explanation:

Given data:

Half life of tritium = 12.3 years

Total mass pf tritium = 48.0 mg

Mass remain after 49.2 years = ?

Solution:

First of all we will calculate the number of half lives.

Number of half lives = T elapsed/ half life

Number of half lives =  49.2 years /12.3 years

Number of half lives =  4

Now we will calculate the amount left after 49.2 years.

At time zero 48.0 mg

At first half life = 48.0mg/2 = 24 mg

At second half life = 24mg/2 = 12 mg

At 3rd half life = 12 mg/2 = 6 mg

At 4th half life =  6mg/2 = 3mg

The amount left after 49.2 years is 3mg.

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Answer:

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What is the volume of a sample of CO2 at STP that has a volume of 75.0mL at 30.0°C and 91kPa
Nezavi [6.7K]

60.7 ml is the volume of a sample of CO2 at STP that has a volume of 75.0mL at 30.0°C and 91kPa.

Explanation:

Data given:

V1 = 75 ml

T1 = 30 Degrees or 273.15 + 30 = 303.15 K

P1 = 91 KPa

V2  =?

P2 = 1 atm or 101.3 KPa

T2 = 273.15 K

At STP the pressure is 1 atm and the temperature is 273.15 K

applying Gas Law:

\frac{P1VI}{T1}= \frac{P2V2}{T2}

putting the values in the equation of Gas Law:

V2 = \frac{P1V1T2}{P2T1}

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4 0
3 years ago
He wants to increase the energy of emitted electrons . Based on the research of Albert Einstein, what is the best way for him to
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To increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.

<h3>What is energy of emitted electron?</h3>

The maximum energy of an emitted electron is equal to the energy of a photon for frequency f (E = hf ), minus the energy required to eject an electron from the metal's surface, also known as work function.

Ee = E - W

<h3>Energy of the emitted electron</h3>

The energy of emitted electrons based on the research of Albert Einstein is given as;

E = hf

where;

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  • f is frequency of incident light on the metal

Thus, to increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.

Learn more about energy of electron here: brainly.com/question/11316046

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2 years ago
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