4 years ago

F(x)=x^3+6x^2+x^1/2 and g(x)=x^1/2 find f(x)/g(x)

1 answer:

6 0

Assuming your f(x) = x^3 +6x^2 +x^(1/2) and g(x) = x^(1/2), you have
.. f(x)/g(x) = x^(5/2) +6x^(3/2) +1

____
If an exponent has any arithmetic in it, parentheses are needed around it.

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If a varies directly as the cube root of b and if a=3 and b=64.find the formula connecting the variables hence find b when a=15/

Liono4ka [1.6K]

Answer:

b = 125

Step-by-step explanation:

Given a varies directly as $\sqrt[3]{b}$ then the equation relating them is

a = k $\sqrt[3]{b}$ ← k is the constant of variation

To find k use the condition a = 3 , b = 64 , then

3 = k $\sqrt[3]{64}$ = 4k ( divide both sides by 4 )

$\frac{3}{4}$ = k

a = $\frac{3}{4}$ $\sqrt[3]{b}$ ← equation of variation

When a = $\frac{15}{4}$ , then

$\frac{15}{4}$ = $\frac{3}{4}$ $\sqrt[3]{b}$ ( multiply both sides by 4 to clear the fractions )

15 = 3 $\sqrt[3]{b}$ ( divide both sides by 3 )

5 = $\sqrt[3]{b}$ , then

b = 5³ = 125

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2 years ago

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puteri [66]

Answer:

Step-by-step explanation:

your equation is -1=7x+b so to put it in y= form, move the -1. your answer is y=7x+1

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