Answer:
81.5g/mol
Explanation:
Molar mass is the ratio between mass of a substance (In this case, 0.207g) and moles presents in this mass.
To solve this question we must find the moles of the gas in order to obtain the molar mass using:
PV = nRT
PV / RT = n
<em>Where P is pressure = 0.980atm</em>
<em>V is volume in Liters = 0.0725L</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is absolute temperature = 68°C + 273.15 = 341.15K</em>
<em />
0.980atm*0.0725L / 0.082atmL/molK*341.15K = n
2.54x10⁻³ moles = n
Thus, the molar mass of the gas is:
0.207g / 2.54x10⁻³ moles
<h3>81.5g/mol</h3>
HCl + NaOH → NaCl + H2O
No. of moles of NaOH = MV/1000
= 3.2X60/1000
= 0.192 mol
**M is your concentration of solution, V is the volume of solution either in cm³ or mL cuz they are equal**
1 mol of NaOH reacted with 1 mol of HCl. No. of moles of HCl needed to react with 0.192mol of NaOH
= 0.192x1/1
= 0.192mol
Volume of HCl = no. of moles x 1000 / M
= 0.192 x 1000 / 4.0
= 48mL
Answer:
Explanation:
Given that:
The work function of the rhodium = 480.5 kJ/mol
It means that
1 mole of electrons can be removed by applying of 480.5 kJ of energy.
Also,
1 mole = 
So,
electrons can be removed by applying of 480.5 kJ of energy.
1 electron can be removed by applying of 
of energy.
Energy required = 
Also,
1 kJ = 1000 J
So,
Energy required = 
Also, 
Where,
h is Plank's constant having value 
c is the speed of light having value 
So,
Also,
1 m = 10⁻⁹ nm
So,
