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3 years ago

What is the pH of 2.0 M nitrous acid at equilibrium (Ka= 4.6×10-4)?

2 answers:

7 0

To find pH, you need this formula: pH= -log [H+]

as you can see, we need to find first the concentration of H+.

you find it, we can use the ka value. Ka is the dissociation constant for acid and it can be used to determine the H+ concentration

Ka= (x)^2/ initial concentration

x = [H+], so all we need to do is solve for X.

ka= 4.6x10-4
initial= 2.0M

so now the formula looks like this:

4.6x10-4= (x)^2/ 2.0

x=0.0303 = [H+]

now that we have the H+ concentration, we can plug it in the pH formula to get our answer

pH= -log (0.0303)= 1.52

Serga [27]3 years ago

5 0

Check out this link to help you. :)
Someone else already answered this question.
brainly.com/question/1489637

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