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3 years ago

Find the slope for the pair of points (1,1)(4,-4)

1 answer:

6 0

(1, 1) and (4, -4)

Slope formula is : m = (y₂-y₁) / (x₂-x₁)

In this case :

x₁ = 1 ; x₂ = 4 ; y₁ = 1 ; y₂ = -4

Now that you know what variable counts as what, we simply just need to plug everything in.

m = (-4 - 1) / (4 - 1)

Simplify.

m = -5/3

Therefore, your slope is -5/3

~Hope I helped~ :)

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The system of equations shown below is graphed on a coordinate grid:

Rufina [12.5K]

Answer:

4x 3 - 6 4 is the answer

Step-by-step explanation:

i took the test in flvs

4 0

3 years ago

A particle is moving along the curve y= 4sqrt(5x+11) . As the particle passes through the point (5,24) , its -coordinate increas

kupik [55]

The rate of change of the distance from the particle to the origin at this instant is 3 units per second.

<h3>What is the rate of change?</h3>

The instantaneous rate of change is the rate of change at a particular instant.

A particle is moving along the curve

$y= 4\sqrt{5x+11} .$

The rate of change of y is given as:

dy / dx = 2

by differentiating both sides,

$\dfrac{dy}{dx} = 4\dfrac{1}{2\sqrt{5x+11} } 5\dfrac{dx}{dt} \\\\\dfrac{dy}{dx} = \dfrac{10}{\sqrt{5x+11} }\dfrac{dx}{dt}\\\\$

From the question, we have:

(x, y) = (5,24)

Substitute 5 for x and dy / dx = 2

$\dfrac{dy}{dx} = \dfrac{10}{\sqrt{5x+11} }\dfrac{dx}{dt}\\\\\\5= \dfrac{10}{\sqrt{5(5)+11} }\dfrac{dx}{dt}\\\\\\\sqrt{5(5)+11} = 2\dfrac{dx}{dt}\\\\\\\dfrac{dx}{dt} = 6/ 2 = 3$

Hence, the rate of change of the distance from the particle to the origin at this instant is 3 units per second.

Read more about rates of change at:

brainly.com/question/13103052

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8 0

1 year ago

A line with a slope of -4 has a coordinate of (0,3). If the other coordinate is (6,t),

s2008m [1.1K]

Answer:

Alrighty! So this is what we know:

Slope (m) = (-4)

Co-ordinate (0,3)

Co-ordinate 2 (6,t)

t = ?

Let's find our equation...

y=mx+b <-- just plug what we know in...

3=(-4)0+b

3=0+b

b=3

We just found b! woohoo

Now what is t? t is a value we need to know WHICH IS the y value of a co-ordinate that corresponds to when x is 6, as we know a co-ordinate is expressed as --> (x value, y value).

SO-

t=y

plug it in our equation...

y=mx+b

t=(-4)x+3

t=(-4)(6)+3

t=(-24)+3

t=(-21)

SOOOOOOOO WE HAVE OUR T!! just write a therefore statement like "therefore the value of t is -21." and you're set! hope this helped, any questions? ask in the comment section. :)

Step-by-step explanation:

7 0

2 years ago

Find the Value of a and b in the triangle below select the two answers fro the list of choices

nataly862011 [7]

For angle a it will be 42degrees and for angle b it will be 138degrees and i am 100%sure

3 0

2 years ago

Read 2 more answers

Let u = (1, 2 -2), v= (2, 1, 3) and w = j + 4k. a) Find cos theta, where theta is the angle in degrees between u and w.

vodka [1.7K]

Answer: The value of cos theta is -0.352.

Step-by-step explanation:

Since we have given that

$\vec{u}=1\hat{i}+2\hat{j}-2\hat{k}\and\\\\\vec{w}=\hat{j}+4\hat{k}$

We need to find the cos theta between u and w.

As we know the formula for angle between two vectors.

$\cos\ \theta=\dfrac{\vec{u}.\vec{w}}{\mid u\mid \mid w\mid}$

So, it becomes,

$\cos \theta=\dfrac{2-8}{\sqrt{1^2+2^2+(-2)^2}\sqrt{1^2+4^2}}\\\\\cos \theta=\dfrac{-6}{\sqrt{17}\sqrt{17}}=\dfrac{-6}{17}=-0.352\\\\\theta=\cos^{-1}(\dfrac{-6}{17})=110.66^\circ$

Hence, the value of cos theta is -0.352.

8 0

3 years ago