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Ivan
4 years ago
7

According to the general equation for conditional probability, if P(ANB)= 3/10 and P(B)= 4/5, what is P(A|B)?

Mathematics
1 answer:
Mars2501 [29]4 years ago
7 0

Answer: 3/8

Step-by-step explanation:

Formula is,

P(A|B) = P(A and B) / P(B)

= (3/10) / (4/5)

= 3/8

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Negative exponents in denominators can be evaluated using StartFraction 1 Over b Superscript negative and EndFraction nbsp equal
skelet666 [1.2K]

Answer:

b Superscript positive

Step-by-step explanation:

Negative exponents in the denominators can be evaluated by moving the function from the denominator to the numerator and changing the power from negative to the positive.

We have

1/b⁻² = b²

Moving the function with a power from denominator to numerator or from numerator to denominator changes the sign of the power. It is not equal to zero.

This is the property of exponents.

3 0
3 years ago
Which is an equivalent form of the expression 1800(1.2)^-t
ololo11 [35]

Answer:

1800(5/6)^t

Step-by-step explanation:

I don't see any answer choices, but this would be another form if it is listed. The negative exponent means that you get the reciprocal of the fraction (in this case 1.2). This turns 1.2 into (1/1.2), which is equivalent to 5/6.

7 0
2 years ago
Homework help please I'll give you 10 points and brainliest
DaniilM [7]

Answer:

c)

Step-by-step explanation:

Use 49 instead of 14 for 7²

Reason: 7² = 7 * 7 = 49

Not 14 as 7*2 = 14

6 0
3 years ago
Consider the numbers 4 and √5. Which operation(s) will result in an irrational number?
tekilochka [14]

Answer: D (both the sum and the product).

Step-by-step explanation:

Let's add: 4 + sqrt5 will still seem irrational.

Let's multiply: 4*sqrt5 = 4sqrt5, which is irrational.

5 0
2 years ago
For a-b, reduce to the least non-negative residue
Olenka [21]

Answer:

  a.  6

  b.  9

Step-by-step explanation:

a. The product modulo 7 can be found from the product of the individual numbers modulo 7:

  (88·95·36·702) mod 7 = (88 mod 7)·(95 mod 7)·(36 mod 7)·(703 mod 7) mod 7

  = (4·4·1·3) mod 7 = 48 mod 7 = 6

__

b. Powers of 4 mod 11 repeat with period 5:

  4 mod 11 = 4

  4^2 mod 11 = 5

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  4^4 mod 11 = 3

  4^5 mod 11 = 1

So, 4^83 mod 11 = 4^3 mod 11 = 9

3 0
3 years ago
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