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butalik [34]
3 years ago
5

Two cars are traveling along a straight road. Car A maintains a constant speed of 95 km/h and car B maintains a constant speed o

f 121 km/h. At t = 0, car B is 41 km behind car A.
(a) How much farther will car A travel before car B overtakes it?km
(b) How much ahead of A will B be 30 s after it overtakes A?km
Physics
1 answer:
natulia [17]3 years ago
8 0

Answer

given,

Speed of car A = 95 Km/h

                         = 95 x 0.278 = 26.41 m/s

Speed of Car B = 121 Km/h

                         = 121 x 0.278 = 33.64 m/s

Distance between Car A and B at t=0 = 41 Km

a) Distance travel by car B

   d = 26.41 t + 41000

speed of the car A = 33.64 m/s

distance = s x t

26.41 t + 41000 = 33.64 x t

7.23 t = 41000

t = 5670.82 s

time taken by Car B to cross Car A is equal to t = 5670.82 s

distance traveled by car A

D = s x t  = 26.41 x 5670.82 = 149766.25 m = 149.76 Km

b) distance travel by the car B in 30 s after overtaking car A

   D' = s x t = 33.64 x 30 = 1009.2 m = 1 Km  

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Answer:

the time Joshua travels 1 mile is 12.5 min

Explanation:

Let's start by finding the distance traveled on each lap,

Let's reduce everything to the SI system

    R = 400 m

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    L = 2 pi R

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Let us form a rule of proportions if 2 turns of Julian is 3 turns Joshua, for 1 turn of Joshua how many turns Julian took

    lap Julian = 2/3 turn Joshua

Let's calculate what distance is the same for both of them since they are on the same track

    1 lap = 2513 m

    d. Julian = 2/3 2513 m

    d Julian = 1675 m distance Joshua

Let us form the last rule of three or proportions if 1609 m you travel in 12 min how long it takes to travel 1675 m

    t Julian = 1675/1609 12

    t = 12.5 s

Since this is the distance Joshua travels, this is the time Joshua travels 1 mile

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A: decreases in specific heat capacity
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When a potential difference of 10 V is placed across a certain solid cylindrical resistor, the current through it is 2 A. If the
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Answer:

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Here since resistivity and length are constant, we only need to see how the resistance increases or decreases with change in area.

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The ratio of new area / old area is :

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Since area increases 9 times, and it is inversely proportional to resistance:

Resistance decreases by 9 times.

So, old resistance = Voltage / Current = 10 / 2 = 5 ohm

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Answer:

346.66 Hz

Explanation:

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l_2 = Length of string which is vibrate when fingered = l-\dfrac{1}{4}l=\dfrac{3}{4}l

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f_2 = Fingered frequency

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So,

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