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3 years ago

What best describes the angle between a changing electric field and the electromagnetic wave produced by it? (2 points)

Physics

2 answers:

Leno4ka [110]3 years ago

6 0

Answer:

Option (A) is the correct answer of this question.

Explanation:

The angle between a changing electric field and the induced electromagnetic wave is always equal to the right angle. The electrical field, the magnetic field and the EM wave are perpendicular. This gives its transverse form to the electromagnetic waves.

A shifting electric field generates a changing magnetic field that in effect causes a changing electrical field.
This means the source has generated a perpendicular to each other, shifting electrical and magnetic fields that travel away from the source.

Electromagnetic (EM) waves shift electrical and magnetic fields, conveying energy and momentum across space.

According to this question, other options are incorrect.

Oksanka [162]3 years ago

4 0

A) always equal to a right angle

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Water flows through a horizontal pipe with a cross-sectional area of 3mat a speed of 10 m/s with a pressure of 3 Bars at a Point

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(a) The speed of the water at point B is 10 m/s and the speed at point C is 5 m/s.

(b) The pressure of the water at point B is 4.96 bars and the pressure at point C is 5.335 bars.

<h3>Speed of the water at point B </h3>

The speed of the water at point B is determined from continuity equation as shown below;

Q = AV

A₁V₁ = A₂V₂

Since, A₁ = A₂ = 3 m²

V₁ = V₂ = 10 m/s

Thus, the speed of the water at point B is 10 m/s.

<h3>Speed of water at point C</h3>

A₁V₁ = A₃V₃

A₁V₁ = (2A₁)V₃

V₃ = (A₁V₁) / 2A₁

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V₃ = 10/2

V₃ = 5 m/s

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<h3>Pressure of the water at point B </h3>

The pressure of the water at point B is determined by appying Bernoulli's equation as shown below;

P₁ + ¹/₂ρV₁² + ρgh₁ = P₂ + ¹/₂ρV₂² + ρgh₂

where;

P₁ = 3 bars = 300,000 Pa
ρ density of water = 1000 kg/m³
g is acceleration due to gravity = 9.8 m/s²

300,000 + ¹/₂(1000)(10)² + (1000)(9.8)(20) = P₂ + ¹/₂(1000)(10)²

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<h3>Pressure of the water at point C</h3>

P₁ + ¹/₂ρV₁² + ρgh₁ = P₃ + ¹/₂ρV₃² + ρgh₃

546,000 = P₃ + ¹/₂(1000)(5)²

546,000 = P₃ + 12,500

P₃ = 533,500 Pa

P₃ = 5.335 bars

Learn more about pressure in horizontal pipe here: brainly.com/question/26761275

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