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-Dominant- [34]
3 years ago
8

What best describes the angle between a changing electric field and the electromagnetic wave produced by it? (2 points)

Physics
2 answers:
Leno4ka [110]3 years ago
6 0

Answer:

Option (A) is the correct answer of this question.

Explanation:

The angle between a changing electric field and the induced electromagnetic wave is always equal to the right angle. The electrical field, the magnetic field and the EM wave are perpendicular. This gives its transverse form to the electromagnetic waves.

  • A shifting electric field generates a changing magnetic field that in effect causes a changing electrical field.
  • This means the source has generated a perpendicular to each other, shifting electrical and magnetic fields that travel away from the source.
  • Electromagnetic (EM) waves shift electrical and magnetic fields, conveying energy and momentum across space.

According to this question, other options are incorrect.

Oksanka [162]3 years ago
4 0

A) always equal to a right angle

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Answer:

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Explanation:

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Your friend decides to generate electrical power by rotating a 100,000 turn coil of wire around an axis in the plane of the coil
MakcuM [25]

Answer:

a) I=35mA

b) P=1.73W

Explanation:

a) The max emf obtained in a rotating coil of N turns is given by:

emf_{max}=NBA\omega

where N is the number of turns in the coil, B is the magnitude of the magnetic field, A is the area and w is the angular velocity of the coil.

By calculating A and replacing in the formula (1G=10^{-4}T) we get:

A=\pi r^2 =\pi(0.23m)^2=0.16m^2

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Finally, the peak current is given by:

I=\frac{emf}{R}=\frac{69.72V}{1400\Omega}=49.8mA

b)

we have that

I_{rms}=\frac{I}{\sqrt{2}}=\frac{0.0498A}{\sqrt{2}}=0.035A

P_{rms}=I^2{rms}R=(0.035A)^2(1400\Omega)=1.73W

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