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myrzilka [38]
3 years ago
15

A book has a mass of 50 grams and an acceleration of 5 m/s/s. What is the force on the book?

Physics
1 answer:
Ivan3 years ago
8 0

Answer:

250 newtons i belive.

Explanation:

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marissa [1.9K]
Need be the needle moves
7 0
3 years ago
How high was a brick dropped from if if falls in 2.5 seconds?
jenyasd209 [6]
Using the kinematic equation d =  V_0 * t  + 1/2 * a * t^2, where d is height you can rewrite this to be d = 1/2*g*t^2 or 4.9t^2
g = a because this is a free fall 
d = 1/2 * 9.81m/s^2 * 2.5^2
d = 30.65625m
d = 30.7m
7 0
3 years ago
Which of the elements below have seven electrons in their outermost energy levels? A.) Cr, Mn, and Fe B.) Br, I, and Ci C.) O, S
Andrei [34K]

Answer:

B

Explanation:

the Halogen families have 7 valence electrons

5 0
3 years ago
The luxury liner Queen Elizabeth 2 has a diesel-electric powerplant with a maximum power of 84 MW at a cruising speed of 35.0 kn
frosja888 [35]

Answer:

F = 4669.201\,kN

Explanation:

Maximum speed is get at maximum power. Let assume that ship travels at constant speed, the expression for power is equal to:

\dot W = F\cdot v

Where F and v are the forward force and speed of ship measured in newtons and meters per second, respectively.

The forward force can be determined by clearing it in the expression described above:

F = \frac{\dot W}{v}

F = \frac{84\times 10^{3}\,kW}{(35\,knots)\cdot \left(\frac{0.514\,\frac{m}{s} }{1\,knot} \right)}

F = 4669.201\,kN

4 0
3 years ago
Read 2 more answers
What will the magnitude of the field be if the 10 nc charge is replaced by a 20 nc charge? Assume the system is big enough to co
MArishka [77]

Answer:

Same magnitude of the 10 nc charge cause the electric field is external.

Explanation:

To do a better explanation, let's go and suppose we have an electric field of, 1300 N/C with a 10 nC charge.

As the system we are talking about is really big, and the charge is small, we can assume always if the charge is sitting right in the same point where the electric field is, then, the electric field would not suffer any kind of alteration in it's value. Therefore, no matter what value of the charge is sitting here, the electric field is independent of the charge, so it would not feel any alteration. However, the force that the charge is feeling would be stronger than in the first case.

F = qE

If charge is doubled, then the force would be bigger in the second case than in the first case, but electric field remain the same value.

4 0
3 years ago
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