Question

3. Two charged boxes are 4 meters apart from each other. The blue box has a charge of +0.000337

Answer 1

Answer:

Charge on the red box is -0.0033 C as it is attracting the blue box

Explanation:

As we know that two boxes are attracting each other

So here we can say that two boxes will have opposite charges

So as we know that electrostatic force between two charges is given as

$F = \frac{kq_1q_2}{r^2}$

here we have

here we know that

$k = 9 \times 10^9$

$q_1 = 0.000337 C$

r = 4 m

F = 626 N

$626 = \frac{(9\times 10^9)(0.000337)q}{4^2}$

$q = 0.0033 C$