Answer:
9
Explanation:
To balance the equation, we need to supply the number of missing coefficients.
There are 2 moles of aluminium on the right hand side, so automatically we need to multiply the number of moles of aluminium by 2 on the left hand side.
There are 3 sulphate ions on the right hand side so we need to multiply the number on the left by 3.
And lastly since we have 6 hydrogen molecules on the left hand side now, we need to multiply the hydrogen on the right hand side by 3 to give 6
The set of coefficients = 2 3 1 3
Adding all thus yields 9
Answer:
MO = 20
Explanation:
Given that: MO = 3x + 5
MN = 2x + 3
NO = 2x - 3
But,
MO = MN + NO
So that;
3x + 5 = (2x + 3) + (2x - 3)
3x + 5 = 2x + 3 + 2x - 3
3x + 5 = 4x
3x - 4x = -5
-x = -5
Multiply through by minus,
x = 5
Thus,
MO = 3x + 5
= 3(5) + 5
= 15 + 5
MO = 20
The length of MO is 20.
Answer:
The chemical equation can be written as:
2Mg+O
2
→2MgO
48 g of Mg reacts with 32 g of O
2
.
Thus, 4.8 g of Mg reacts with 3.2 g of O
2
.
Now, 32 g of O
2
forms = 80 g of MgO.
3.2 g of O
2
produces =
32
80
×3.2 = 8 g of MgO.
Was this answer helpful?
MARK ME AS BRAINLIEST
Fe2O3 + 2Al ---> Al2O3 + 2Fe
Mole ratio Fe2O3 : Al = 1:2
No. of moles of Fe2O3 = Mass/RMM = 250 / (55.8 * 2 + 16 * 3) = 1.56641604 moles
No. of moles of Al = 150/27 = 5.555555555 moles.
Mole ratio 1 : 2. 1.56641604 * 2 = 3.13283208 moles of Al, but you have 5.555555555 moles of Al. So Al is in excess. All of it won't react.
So take the Fe2O3 and Fe ratio to calculate the mass of iron metal that can be prepared.
RMM of Fe2O3 / Mass of Fe2O3 = RMM of 2Fe / Mass of Fe 159.6 / 250 = 111.6 / x x = 174.8 g of Fe
Number of electron determine reactivity
